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saw5 [17]
3 years ago
8

How much work is done against gravity when lowering a 16 kg box 0.50 m? (g = 9.8 m/s2)

Physics
1 answer:
leonid [27]3 years ago
6 0

Answer:

The work done against gravity is 78.4 J

Explanation:

The work is calculated by multiplying the force by the distance that the

object moves

W = F × d, where W is the work , F is the force and d is the distance

The SI unit of work is the joule (J)

We need to find the work done against gravity when lowering a

16 kg box 0.50 m

→ F = mg

→ m = 16 kg, and g = 9.8 m/s²

Substitute these value in the rule

→ F = 16 × 9.8 = 156.8 N

→ W = F × d

→ F = 156.8 N and d = 0.50

Substitute these values in the rule

→ W = 78.4 J

<em>The work done against gravity is 78.4 J</em>

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Answer:

at the beginning: 2.3\cdot 10^{-10} F

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A is the area of the plates of the capacitor

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A=0.210 m^2 is the area of the plates

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Later, the plates are pulled apart to d=1.63 cm=0.0163 m, so the capacitance becomes

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