Answer:
- 1.3 x 10⁻¹⁵ C/m
Explanation:
Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C
r = Radius of the arc = 5.30 cm = 0.053 m
θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad (Since 1 deg = 0.0175 rad)
L = length of the arc
length of the arc is given as
L = r θ
L = (0.053) (0.84)
L = 0.045 m
λ = Linear charge density
Linear charge density is given as
Inserting the values
λ = - 1.3 x 10⁻¹⁵ C/m
Answer : The value of is 286.2 J and 286.2 J respectively.
Explanation : Given,
Moles of sample = 0.877 mol
Change in temperature = 15.7 K
First we have to calculate the heat absorbed by the system.
Formula used :
where,
q = heat absorbed by the system = ?
n = moles of sample = 0.877 mol
= Change in temperature = 15.7 K
= heat capacity at constant volume of
(diatomic molecule) =
R = gas constant = 8.314 J/mol.K
Now put all the given value in the above formula, we get:
Now we have to calculate the change in internal energy of the system.
As we know that, work done is zero at constant volume. So,
Therefore, the value of is 286.2 J and 286.2 J respectively.