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PtichkaEL [24]
3 years ago
9

20 POINTS What is an endothermic reaction?​

Physics
2 answers:
Ratling [72]3 years ago
7 0

Answer:

An endothermic reaction is a chemical reaction in which more energy is needed to break bonds in the reactants than is released when new bonds form in the products.

A constant input of energy, often in the form of heat, is needed to keep an endothermic reaction going.

Explanation:

A would be the answer

tiny-mole [99]3 years ago
3 0

Answer:

A reaction that contributes energy to the surroundings

Explanation:

When energy is taken in from the Surroundings, the temperature of the surroundings decreases

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a dock worker pushes a 150.0 kg crate up a ramp that is 3.00 m high and 10.00 m long into the cargo bay of a ship. He exerts a 8
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Efficiency: (2940 J / 3250 J) x 100% = 90.46%

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Physical fitness is related to our ability to carry out daily tasks without being too tired or sore. Please select the best answ
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Physical fitness is related to our ability to carry out daily tasks without being too tired or sore. This statement is TRUE.  

<h3>Further explanation </h3>

Good physical fitness means that you can perform daily activities, occupations, and sports. This condition will be achieved through good nutrition, regular exercise, and have enough rest.  

The benefit of physical activity and exercise can be immediate as well as long-term. Most importantly, regular activity can improve your quality of life.There are four types of physical fitness:

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7 0
4 years ago
Read 2 more answers
Ezra (m = 20.0 kg) has a tire swing and wants to swing as high as possible. He thinks that his best option is to run as fast as
Dmitriy789 [7]

Answer:

a) v=5.6725\,m.s^{-1}

b) h= 1.6420\,m

Explanation:

Given:

  • mass of the body, M=20\,kg
  • mass of the tyre,m=10\,kg
  • length of hanging of tyre, l=3.5m
  • distance run by the body, d=10m
  • acceleration of the body, a=3.62m.s^{-2}

(a)

Using the equation of motion :

v^2=u^2+2a.d..............................(1)

where:

v=final velocity of the body

u=initial velocity of the body

here, since the body starts from rest state:

u=0m.s^{-1}

putting the values in eq. (1)

v^2=0^2+2\times 3.62 \times 10

v=8.5088\,m.s^{-1}

Now, the momentum of the body just before the jump onto the tyre will be:

p=M.v

p=20\times 8.5088

p=170.1764\,kg.m.s^{-1}

Now using the conservation on momentum, the momentum just before climbing on the tyre will be equal to the momentum just after climbing on it.

(M+m)\times v'=p

(20+10)\times v'=170.1764

v'=5.6725\,m.s^{-1}

(b)

Now, from the case of a swinging pendulum we know that the kinetic energy which is maximum at the vertical position of the pendulum gets completely converted into the potential energy at the maximum height.

So,

\frac{1}{2} (M+m).v'^2=(M+m).g.h

\frac{1}{2} (20+10)\times 5.6725^2=(20+10)\times 9.8\times h

h\approx 1.6420\,m

above the normal hanging position.

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Ksivusya [100]

Answer:

1) Charges

2) Vectors

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