Answer:
The maximum number of quarters that he could have is 13
Step-by-step explanation:
Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then
→ x + 10 >= 20
→ x >= 10 (1)
His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.
→ (x * 25) + (10 * 10) <= (4.25 * 100)
→ 25x + 100 <= 425
→ 25x <= 325
→ x <= 13 (2)
If we combine the equation 1 and 2:
10 <= x <= 13
The maximum value of x is 13
7y + 5x is another way to write it, is there anything specific you're looking for
If you're trying to find the perimeter of a specific problem, you can add a file. To solve perimeter for any problem, you add all the side lengths. Hope that helps! :)
The answer is the point lies directly on the regression line.
24 quaters because 4*6=24
