"Decaying swamps are covered with seawater" step ONLY occurs in the formation of coal.
<u>Option:</u> B
<u>Explanation:</u>
Coal production continues in regions of swampy wetlands because groundwater is near to or just above the topsoil. Because of this, organic matter is created quickly by the flora present-faster even than it can be broken down. Layers of organic matter are deposited in these areas, and then buried.
Based on the plants and circumstances present, the mechanism that produces coal varies somewhat in various areas but the ultimate method is similar. Coal production has two primary phases: peatification, and coalification. It is a solid black, readily combustible fossil fuel containing a large quantity of carbon-based material-about 50 percent of its mass.
Answer:
17.65 grams of O2 are needed for a complete reaction.
Explanation:
You know the reaction:
4 NH₃ + 5 O₂ --------> 4 NO + 6 H₂O
First you must know the mass that reacts by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). For that you must first know the reacting mass of each compound. You know the values of the atomic mass of each element that form the compounds:
- N: 14 g/mol
- H: 1 g/mol
- O: 16 g/mol
So, the molar mass of the compounds in the reaction is:
- NH₃: 14 g/mol + 3*1 g/mol= 17 g/mol
- O₂: 2*16 g/mol= 32 g/mol
- NO: 14 g/mol + 16 g/mol= 30 g/mol
- H₂O: 2*1 g/mol + 16 g/mol= 18 g/mol
By stoichiometry, they react and occur in moles:
- NH₃: 4 moles
- O₂: 5 moles
- NO: 4 moles
- H₂O: 6 moles
Then in mass, by stoichiomatry they react and occur:
- NH₃: 4 moles*17 g/mol= 68 g
- O₂: 5 moles*32 g/mol= 160 g
- NO: 4 moles*30 g/mol= 120 g
- H₂O: 6 moles*18 g/mol= 108 g
Now to calculate the necessary mass of O₂ for a complete reaction, the rule of three is applied as follows: if by stoichiometry 68 g of NH₃ react with 160 g of O₂, 7.5 g of NH₃ with how many grams of O₂ will it react?

mass of O₂≅17.65 g
<u><em>17.65 grams of O2 are needed for a complete reaction.</em></u>
Barium chloride and lithium sulfate are mixed, barium sulfate and lithium chloride are formed. Barium sulfate is obtained as a white precipitate and lithium chloride as an aqueous solution.
Hope it helped!
The remaining 90% transforms into Hydrogen and Oxygen. The remaining 90% is recombined to maker larger molecules. I think
Answer:
Is that all of the problem??
Explanation: