Question

When solutions of barium chloride and lithium sulfate are mixed, the spectator ions in the resulting reaction are?

Answer 1

Barium chloride and lithium sulfate are mixed, barium sulfate and lithium chloride are formed. Barium sulfate is obtained as a white precipitate and lithium chloride as an aqueous solution.

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Answer 2

Answer : The resulting reaction will be,

$Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$BaCl_2(aq)+Li_2SO_4(aq)\rightarrow BaSO_4(s)+2LiCl(aq)$

The ionic equation in separated aqueous solution will be,

$Ba^{2+}(aq)+2Cl^-(aq)+2Li^+(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)+2Li^+(aq)+2Cl^-(aq)$

In this equation, $Li^+\text{ and }Cl^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)$