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3 years ago

12

What is 8/10 subtract 5/10

1 answer:

anzhelika [568]3 years ago

4 0

Since the denominators are the same, just subtract the numerators.
The answer is 3/10.

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Drag each label to the correct location on the table . Triangle EFG . Rectangle PQRS . Triangle TUV . Rectangle ABCD . Your choi

Tanya [424]

Answer:

there should be a pic or a diagram

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=

KiRa [710]

$e ^{2x} = ln5$

Solve for the real domain

$e ^{2x} = ln(5)$

if $f(x) =g(x),$ then $ln(f(x))= ln(g(x))$

$ln(e ^{2x} ) = ln(ln(5))$

Solve : <span> $ln(e ^{2x} ) = ln(ln(5))$
</span>
use the logarithmic definition :

$ln(e^{f(x)} ) = f(x)$

$ln(e^{2x} ) = 2x$

$2x=ln(ln(5))$

Divide both sides by 2 :

$\frac{2x}{2} = \frac{ln(ln(5))}{2}$

$x= \frac{ln(ln(5))}{2}$

hope this helps!

8 0

3 years ago

Suppose you deposit $6000 in a savings account that pays interest at an annual rate of 4% compounded continuously. In 8 years, w

Semenov [28]

Idk sorry for that ‍♀️‍♀️

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3 years ago

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Determine the currents in the picture

Evgesh-ka [11]

Answer:

The value of currents are $I_1=0A$ , $I_2=1A$ and $I_3=1A$ .

Step-by-step explanation:

The Ohm's law states that

$V=IR$

It is given that the V₁=3V and V₂=4V.

In a parallel circuit:

→ Voltage is same in each component

→ Sum of the currents equals to the total current that flows.

$I_2=I_1+I_3$ .... (1)

Equation for first loop is,

$V_1=4I_1+3I_2$

$3=4I_1+3I_2$ ..... (2)

Equation for second loop is,

$V_2=1I_3+3I_2$

$4=1I_3+3I_2$ ..... (3)

On solving (1), (2) and (3) we get

$I_1=0$

$I_2=1$

$I_3=1$

Therefore the value of currents are $I_1=0A$ , $I_2=1A$ and $I_3=1A$ .

4 0

3 years ago

Brainiest if your right

Ivanshal [37]

i would say the answer is 5/8

because c is 3/4

4 0

3 years ago