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3 years ago

Givereasons for the following.

Physics

1 answer:

Scrat [10]3 years ago

3 0

a. Pascal is a derived unit because it is depend upon fundamental unit like as Kg, Meter, and Sec.

b. Mass is a fundamental quantity because it is independent with other.

c. Unit of power is a derived unit because it is depend upon fundamental unit like as Kg, Meter, and Sec.

d. Unit of length is a fundamental quantity because it is independent with other.

I hope you understand...

Thanks♥♥

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Why are some scientists skeptical of the scientists results and conclusions

babunello [35]

Earth's surface temperature has warmed 1.5 degrees Celsius over the past 250 years and "humans are almost entirely the cause," concludes a scientific study designed to address skeptical concerns that the causes of climate change are even induced. for the man. Professor Richard Muller, a climate change physicist and founder of the Berkeley Earth Surface Temperature Project, said he was surprised by the findings. "We did not expect this result, but as scientists it is our duty to let the evidence change our minds." He added that he now considers himself a "converted skeptic" and his views have been subjected to a "total turnaround" in a short time. "Our results show that the average land surface temperature has increased by 1.5 degrees Celsius over the last 250 years, including an increase of 0.9 degrees Celsius over the last 50 years. In addition, it seems likely that essentially all of this increase results from human emissions of greenhouse gases, ”Muller wrote in an article in the New York Times. The University of California, Berkeley-based team of scientists has assembled and consolidated a set of 14.4 million surface temperature observations, collected from 44,455 sites worldwide, dating back to 1753. Previous datasets created by NASA and the National Oceanic and Atmospheric Administration (NOAA) in the US, and by the Met Office and the Department of Climate Research at the University of East Anglia in the United Kingdom only arrived until the mid-19th century and used only a fifth of the number. of weather station records

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3 years ago

A 270 g bird flying along at 5.0 m/s sees a 11 g insect heading straight toward it with a speed of 35 m/s (as measured by an obs

mote1985 [20]

Answer:

The bird's speed immediately after swallowing is 6.17 m/s.

Explanation:

Given that,

Mass of the bird, m = 270 g = 0.27 kg

Initial speed of the bird, u = 5 m/s

Mass of the insect, m' = 11 g = 0.011 kg

Initial speed of the insect, u' = 35 m/s

We need to find the bird's speed immediately after swallowing. Let it is given by V. Using the conservation of momentum as :

$mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{0.27\times 5+0.011\times 35}{(0.27+0.011)}\\\\V=6.17\ m/s$

So, the bird's speed immediately after swallowing is 6.17 m/s.

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3 years ago

1) The current in a light bulb is 0.335 Amps. How long does it take for a total charge of 2.76 C to

uysha [10]

Answer:

Time=8.23880597 seconds

Explanation:

Quantity of charge(q)=2.76c

Current(I)=0.335A

Time(t)=?

t=q/I

t=2.76/0.335

t=8.23880597seconds

7 0

3 years ago

Two small spheres assumed to be identical conductors are placed at 30 cm from each other on a horizontal axis. the first S1 is l

charle [14.2K]

a) The electric force exerted by S1 on S2 is 21.58μN.

In this case we are talking about two different types of charges, a positive charge and a negative charge, therefore, they are sensing a force of attraction.

The magnitude of the force is determined by using the following formula:

$F_{e}=k_{e}\frac{|q_{1}||q_{2}|}{r^{2}}$

where:

= Electric force [N]

= Electric constant ()

= First charge [C]

= Second charge [C]

r = distance between the two charges

So, in this case, the force can be calculated like this:

$F_{e}=(8.99x10^{9}N\frac{m^{2}}{C^{2}})\frac{|12x10^{-9}C||18x10^{-9}C|}{(30x10^{-2}m)^{2}}$

So the force will be equal to:

$F=21.58x10^{-6}N$

which is the same as:

$F=21.58 \micro N$

b) The electric field created by S1 at the level of S2 is $1.20 \frac{kN}{C}$

The electric field tells us how many Newtons of force can be applied on a given point in space per unit of charge caused by an existing electric charge. From the concept, we can take the following formula for the electric field.

$E_{S1}=\frac{F_{e}}{q_{2}}$

where:

= electric field generated by the first sphere.

$E_{S1}=\frac{1.20 x10^{-6}N}{18x10^{-9}C}$

which yields:

$E_{S1}=1.20x10^{3} \frac{N}{C}$

$E_{S1}=1.20 \frac{kN}{C}$

When talking about electric fields, we know what their direction is if we suppose the electric field is always affecting a positive charge in the given point in space. In this case, since S1 is positive, we can asume the electric field is in a direction away from S1.

The electric potential created by S1 at the level or S2 is 360V

Electric potential is defined to be the amount of energy you will have at a given point per electric charge. This electric potential can be found by using the following formula:

V=Er

Where V is the electric potential and it is given in volts.

Volts are defined to be 1 Joule per Coulomb. Energy by electric charge.

So we can use the data found in the previous sections to find the electric potential:

$V=(1.20x10^{3} \frac{N}{C})(30x10^{-2}m)$

V=360V

d) The force exerted by S2 on S1 will be the same in magnitude as the force exerted by S1 on S2 but oposite in direction. This is because the force will depend on the two charges, and the distance between them, so:

The electric force exerted by S1 on S2 is 21.58μN.

The magnitude of the force is determined by using the following formula:

$F_{e}=k_{e}\frac{|q_{1}||q_{2}|}{r^{2}}$

$F_{e}=(8.99x10^{9}N\frac{m^{2}}{C^{2}})\frac{|12x10^{-9}C||18x10^{-9}C|}{(30x10^{-2}m)^{2}}$

So the force will be equal to:

$F=21.58x10^{-6}N$

which is the same as:

$F=21.58 \micro N$

e) The electric field generated by S1 in the middle of S1 and S2 is $4.79 \frac{kN}{C}$

In order to find the electric field generated by S1, we can make use of the following formula

$E=k_{e} \frac{q_{1}}{r_{1}^{2}}$

$E=(8.99x10^{9} N\frac{m^{2}}{C^{2}})(\frac{12x10^{-9}C}{(15x10^{-2}m)^{2}})$

which yields:

$E=4.79 \frac{kN}{C}$

f) The electric field in the middle of S1 and S2 is $11.99 \frac{kN}{C}$

In order to find the electric field generated by two different charges at a given point is found by using the following formula:

$E=k_{e} \sum \frac{q_{i}}{r_{i}^{2}}$

where:

$q_{i}$ = each of the charges in the system

$r_{i}$ = the distance between each of the charges and the point we are analyzing.

Since the electric field is a vector, we need to take into account the individual electric fields' directions. In this case we suppose we have a positive test charge between the two charges. We can see that the positive test charge will sense a force in the same direction independently on if the force is excerted by the positive charge or the negative charge. Therefore both electric fields will have the same direction. We'll suppose the electric fields will be positive then, so:

$E=(8.99x10^{9} N\frac{m^{2}}{C^{2}})[\frac{12x10^{-9}C}{(15x10^{-2}m)^{2}}+\frac{18x10^{-9}C}{(15x10^{-2}m)^{2}}]$

which yields:

$E=11.99 \frac{kN}{C}$

g) The electric potential in the middle of S1 and S2 is 1.80 kV

Since we know what the electric field is from the previous question, we can make use of the same formula we used before to find the electric potential in the middle of S1 and S2

So let's take the formula:

V=Er

So we can use the data found in the previous sections to find the electric potential:

$V=(11.99x10^{3} \frac{N}{C})(15x10^{-2}m)$