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Eddi Din [679]
3 years ago
12

Suppose a lion running at a velocity of 10 m/s east slows

Physics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

a=0.34\ m/s^2

Explanation:

Given that,

Initial velocity, u = 10 m/s

Final velocity, v = 0 (stops)

Time, t = 30 s

We need to find the acceleration of the lion.

We know that,

Acceleration = rate of change of velocity

a=\dfrac{v-u}{t}\\\\a=\dfrac{10-0}{30}\\\\a=0.34\ m/s^2

So, the acceleration of the lion is 0.34\ m/s^2.

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The average power is 3.0\cdot 10^6 W

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where :

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

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v = 60 m/s is the final speed of the car

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

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Soolving:

W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J

Now we can find the power required for the acceleration, which is given by

P=\frac{W}{t}

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t = 9 s is the time elapsed

Solving:

P=\frac{2.7\cdot 10^6}{9}=3.0\cdot 10^6 W

Learn more about power:

brainly.com/question/7956557

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