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Ludmilka [50]
3 years ago
14

What is 52,427 equal in scientific notation

Physics
2 answers:
coldgirl [10]3 years ago
5 0

You can write 52,227 as 5.2427×10-⁴

Ivanshal [37]3 years ago
4 0

Answer: 5.2427 x 10^{4}

Explanation: To write a number in scientific notation, first write a decimal point in the number so there is only 1 digit to the left of the decimal point.

So here, we have 5.2427 and notice that there is only 1 digit to the left of the decimal point. Next, we count the number of places the decimal point would need to move to get back to the original number 52,427.

Since we would need to move the decimal point 4 places to the right, we have an exponent of positive 4.

Now, Scientific notation is always expressed as a number times a power of 10. So in this case we have 5.2427 x 10^{4}.

So 52,427 can be written in scientific notation as 5.2427 x 10^{4}.

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A spring on a horizontal surface can be stretched and held 0.5 m from its equilibrium position with a force of 60 N. a. How much
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Answer:

a)1815Joules b) 185Joules

Explanation:

Hooke's law states that the extension of a material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically;

F = ke where;

F is the applied force

k is the elastic constant

e is the extension of the material

From the formula, k = F/e

F1/e1 = F2/e2

If a force of 60N causes an extension of 0.5m of the string from its equilibrium position, the elastic constant of the spring will be ;

k = 60/0.5

k = 120N/m

a) To get the work done in stretching the spring 5.5m from its position,

Work done by the spring = 1/2ke²

Given k = 120N/m, e = 5.5m

Work done = 1/2×120×5.5²

Work done = 60× 5.5²

Work done = 1815Joules

b) work done in compressing the spring 1.5m from its equilibrium position will be gotten using the same formula;

Work done = 1/2ke²

Work done =1/2× 120×1.5²

Works done = 60×1.5²

Work done = 135Joules

8 0
3 years ago
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d

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He generation of a magnetic field by an electric current is
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Answer: electromagnetism.

Explanation:The use of coils of wires produces a relationship between electricity and magnetism that gives us another magetism called electromagnetism.

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What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
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The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

<h3>Change in energy level of the electron</h3>

When photons jump from a higher energy level to a lower level, they emit or radiate energy.

The change in energy level of the electrons is calculated as follows;

ΔE = Eb - Ef

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ΔE = 3.06 eV

Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

Learn more about energy level here: brainly.com/question/14287666

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