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Answer:
Hence, the following equations, when graphed, intersect at the point (4, 0):
x - y = 4 (1)
x + y = 4 (4)
Step-by-step explanation:
<em>" For the graph to intersect at the point (4,0) we mean that when y=0 , x must be equal to 4 or we could say that when x=4 then y=0".</em>
1)
x-y=4
now when y=0 then x=4.
Hence, the graph intersect at the point (4,0).
2)
-x-y=4
When y=0 in the equation then x=-4, Hence the point (4,0) does not lie on the graph of the given function.
3)
2x-y=7
When y=0 then x=7/2.
Hence the graph of the function does not intersect at the point (4,0).
4)
x+y=4
When y=0 then x=4.
Hence the graph of the given function intersect at (4,0).
5)
2x + y = 7
When y=0 then x=7/2.
Hence the graph of the function does not intersect at the point (4,0).
6)
2x + y = -7
When y=0 then x= -7/2.
Hence the graph of the function does not intersect at the point (4,0).
The quadratic graph crosses the y-axis at -3, so the equation is 
The shaded region is on 'outer' part of the graph, hence the inequality is
The shaded region is on 'outer' part of the graph, hence the inequality is