Muscle is the newer hope it helps
Answer:
The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Explanation:
Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen using Lead (IV) oxide as a catalyst.
- The catalyst surface area is directly proportional to the reaction rate
- So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.
2. Also, Removing lead (IV) oxide from the reaction mixture the reaction rate decreased because as the catalyst is removed.
3. Using 50 cm³ of hydrogen peroxide doesn't affect the rate because the concentration of the reactant doesn't change.
4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased
So, The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Answer:
A) high spin complex
B) low spin complex
Explanation:
A) VCI3(H20)3 is a high spin complex and this is because the complex has a weak field ligands all . this weak field ligands makes it impossible for pairing to take place
B) Fe(NH3)23 is a low spin complex and this is because the complex is made up of strong field ligands, this strong field ligands makes it possible for paring to take place
note : Ligands in which its donor atoms are ; Nitrogen,phosphorous or carbon are considered strong ligands
