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riadik2000 [5.3K]
3 years ago
7

When an unknown substance is dissolved in water, hydronium ions form. What can you conclude about the substance? @thomaster

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0
HIdronium ions, H3O +, are formed as consequence of protonation of water.

The protons that cause this protonation come from acids.

Then, you can infere that the substance is an acid.
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antiseptic1488 [7]

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3 0
2 years ago
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Write an ionic equation for the reaction of acetic acid with sodium ethoxide, and specify whether the equilibrium favors startin
Elina [12.6K]
<h2>Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide</h2>

Explanation:

An ionic equation for the reaction of acetic acid with sodium ethoxide is as follows -

  • Reactants -

       Acetic Acid and Sodium ethanolate (sodium ethoxide)

  • Products -

       Butyric Acid and Sodium hydroxide

Hence,

     Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide

     CH_3COOH + C_2H_5ONa ⇄ CH_3COOC_2H_5 + NaOH

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  • The chemical equilibria shift the reaction side with the species having lower energy.
  • Given reaction is an acid-base reaction in which the equilibrium favors the starting material that means it will go to the side of the weakest acid that is acetic acid is weaker than butyric acid.
6 0
3 years ago
Which is TRUE of the reactants in this displacement reaction? Fe + 2HCI --&gt; FeCI2 + H2
Masteriza [31]
I would go with C, because you would always start with products and end with reactants.
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A solution of hydrochloric acid (HCl, 25.00 mL) was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What was
kati45 [8]

Answer:

0.1410 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This include:

Volume of acid, HCl (Va) = 25 mL

Volume of base, NaOH (Vb) = 34.55 mL

Concentration of base, NaOH (Cb) = 0.1020 M

Concentration of acid, HCl (Ca) =?

CaVa / CbVb = nA/nB

Ca × 25 / 0.1020 × 34.55 = 1/1

Ca × 25 / 3.5241 = 1/1

Cross multiply

Ca × 25 = 3.5241 × 1

Ca × 25 = 3.5241

Divide both side by 25

Ca = 3.5241 / 25

Ca = 0.1410 M

Therefore, the concentration of the acid, HCl is 0.1410 M

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3 years ago
When the solid and liquid phases are present together simultaneously which phase solid liquid contains the greater amount of ene
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Liquid because it is changing to that  <span />
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