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riadik2000 [5.3K]
3 years ago
7

When an unknown substance is dissolved in water, hydronium ions form. What can you conclude about the substance? @thomaster

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0
HIdronium ions, H3O +, are formed as consequence of protonation of water.

The protons that cause this protonation come from acids.

Then, you can infere that the substance is an acid.
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Key words how atoms work?
pantera1 [17]
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I hope this helps you! :D
3 0
3 years ago
Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO
zavuch27 [327]

Answer:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Explanation:

Hello,

In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons  4NOBr ( g )

The suitable equilibrium constant turns out:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Or in terms of the initial equilibrium constant:

K_2=K_1^2

Since the second reaction is a doubled version of the first one.

Best regards.

5 0
3 years ago
You have 20 g of a buckyball (C20) .
gregori [183]
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3 0
3 years ago
A chemist encounters an unknown metal. They drop the metal into a graduated cylinder containing water, and find the volume chang
Mashutka [201]

Answer:

The density of the metal is 0.561 g/mL

Explanation:

The computation of the density of the metal is shown below;

As we know that

The Density of the metal is

= \frac{mass}{volume}

where,

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Now place these values to the above formula

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= \frac{4.9g}{6.9mL}

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Hence, the density of the metal is 0.561 g/mL

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