We have that the the liquid is
- C_2H_5OH (ethanol
- And at a condition of H_2SO4 as catalyst and temp 170
From the question we are told
- A student wished to prepare <em>ethylene </em>gas by <em>dehydration </em>of ethanol at 140oC using sulfuric acid as the <em>dehydrating </em>agent.
- A low-boiling liquid was obtained instead of ethylene.
- What was the liquid, and how might the reaction conditions be changed to give ethylene
<h3>
Ethylene formation</h3>
Generally the equation is
2C_2H_5OH------CH3CH_2O-CH_2CH_3+H_20
Therefore
with ethanol at 140oC
The product is diethyl ethen
The reaction at 170 ethylene will give
C_2H_5OH-------CH_2=CH_2+H_2O( at a condition of H_2SO4 as catalyst and temp 170)
Therefore
The the liquid is
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Answer:
24
Explanation:
The number of protons in the atom of the neutral element will also be 24.
Protons are the positively charged particles in an atom.
Electrons are the negatively charged particles
Neutrons do not carry any charges at all
Now, in a neutral atom, the charge is balanced and the number of protons and electrons are the same in the atom.
So, since we have been given that the atom has 24 electrons, the number of protons will be 24.
It simply equals 4x-16.......
the expression is in lowest terms, so you can’t do anything else
