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kaheart [24]
2 years ago
5

How can scientists detect blood doping?

Chemistry
2 answers:
aev [14]2 years ago
6 0

Answer:

There are typically three ways that it is accomplished: use of erythropoietin (EPO) or synthetic oxygen carriers and blood transfusions. While transfusions of large volumes of blood or use of EPO can be detected, microdosing EPO or transfusing smaller volumes of packed red blood cells is much harder to detect.

vesna_86 [32]2 years ago
6 0

Answer:

Explanation:

Blood doping via homologous transfusion can be detected by testing. The tests were used at the 2004 Summer Olympic Games in Athens, Greece. EPO injections. Blood and urine tests can detect the presence of synthetic EPO

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The reaction of ammonia and hydrogen chloride gas:
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It's replacement reaction. Hope it helped
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3 years ago
For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this
Salsk061 [2.6K]

The following are the steps  to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3                           N = +5                        

O = -2                            O = -2

Ag = +1                         Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

     NO2– -----> NO3–

     Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

     NO2– + H2O -----> NO3–

     Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

    NO2– + H2O -----> NO3– + 2H+

     Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     2 Ag+ + 2e------> 2 Ag(s)

3 0
3 years ago
What is 0.000980 in scientific notation
JulijaS [17]

Answer:

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Explanation:

5 0
3 years ago
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A heat energy of 645 J is applied to a sample of glass with a mass of 28.4 g. Its temperature increases from –11.6 ∞C to 15.5 ∞C
Anika [276]
The heat that is required to raise the temperature of an object is calculated through the equation,
                        heat = mass x specific heat x (T2 - T1)
Specific heat is therefore calculated through the equation below,
                                specific heat = heat / (mass x (T2 - T1))
Substituting,
                                specific heat = 645 J / ((28.4 g)(15.5 - - 11.6))
The value of specific heat from above equation is 0.838 J/g°C. 
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3 years ago
If temperature is held constant for an ideal gas, as P and V change for a given gas sample, the PV of products will_____. increa
vodka [1.7K]

Answer:

PV=nRT

Explanation:

V=<u>R</u><u>T</u><u>n</u>

P

rearrangement gives

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nT

where P=pressure

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T=temperature in kelvin

3 0
3 years ago
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