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rjkz [21]
3 years ago
7

10 grams of sodium hydroxide, NaOH, is dissolved in 0.25 liters of solution. Determine the molarity (M).

Chemistry
1 answer:
lozanna [386]3 years ago
3 0

Answer:

1M

Explanation:

The molarity of a substance is defined as the number of moles of the substance divided by how many liters the solution is. NaOH has a molar mass of about 40 grams, meaning that 10 grams of it would be 0.25 moles. 0.25/0.25= a molarity of 1.

Hope this helps!

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Process of transformation of CH3CH2CH2CH2CL to CH3CH(OH)CH(OH) CH3​
egoroff_w [7]

Answer:

Prefixes for carbon chain length are  

1 carbon = meth  

2 carbon = eth  

3 = prop  

4 = but  

5 = pent  

6 = hex  

7 = hept  

8 = oct  

9 = non  

10 = dec

Explanation:

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3 years ago
inside a wave describe the motion of water particles as the wave particles as the wave passes through​
Kipish [7]

In a water wave all particles travel in clockwise circles.

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2 years ago
The first task you are assigned in your summer laboratory job is to prepare a concentrated naoh stock solution. the molecular we
tensa zangetsu [6.8K]

240 g NaOH

<em>Step 1</em>. Calculate the moles of NaOH

Moles of NaOH = 0.750 L solution × (8 mol NaOH/1 L solution) = 6 mol NaOH

Step 2. Calculate the mass of NaOH

Mass of NaOH = 6 mol NaOH × (40 g NaOH/1 mol NaOH) = 240 g NaOH

7 0
3 years ago
3. How much heat is required to raise the temperature of 179g of acetic acid, CH3COOH, from 250C
IgorLugansk [536]

Answer:

Q = 1252.82kJ

Explanation:

Mass = 179g

Initial temperature (T1) = 25°C = (25+273.15)K = 298.15K

Final temperature (T2) = 82.70°C = (82.70 + 273.15)K = 335.85K

Specific heat capacity (c) = 121.3J/g.K

Heat energy (Q) = mc∇T

M = mass of the substance

Q = heat energy

c = specific heat capacity of the substance

∇T = change in temperature of the substance = T2 - T1

Q = mc∇T

Q = 179 × 121.3 × (355.85 - 298.15)

Q = 21712.7 × 57.7

Q = 1,252,822.79

Q = 1252.82kJ

The heat energy required to heat 179g of acetic acid from 25°C to 82.70°C is 1252.82kJ

3 0
2 years ago
What is the correct order for the reactions that produce the following transformation. a. (1) H2/Lindlar (2) CH3CO2OH b. (1) H2/
Basile [38]

Answer:

Explanation:

Can you provide a picture? I can outline the reactions though. a) will make a Z double bond from a triple bond and then peroxyacid can do epoxidation. b) will make the Z double bond then ozonolysis to double bond will create to aldehyde compounds. c) is essentially useless unless there is a ketone or aldehyde in the compound already since H2/Pd will fully reduce the alkyne (which I am assuming is present) and so the peroxyacid can't do epoxidation and can only do baeyer villiger oxidation, and d) reduces the alkyne to an E alkene and then do epoxidation to give an epoxide (with trans steroechemistry)

4 0
3 years ago
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