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alex41 [277]
3 years ago
14

Scientific law describes what nature does under certain conditions

Chemistry
1 answer:
RideAnS [48]3 years ago
4 0

Answer A scientific law is a statement that describes what always happens under certain conditions in nature. An example of a scientific law is the law of gravity, which was discovered by Sir Isaac Newton. The law of gravity states that objects always fall towards Earth because of the pull of gravity.

Explanation:

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If there is a disturbance to a chemical system at equilibrium, then the<br> ystem will
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Explanation:

Basically

The concentration of reactants and the products becomes equal at equilibrium. The equilibrium position is changed if the concentration of the species in the mixture is changed.

  • the disturbance causes a change in Q; the reaction will shift to re-establish Q=K.
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4 years ago
Brad is swimming in the ocean on a hot sunny day. He finds the water to be much colder than the sand on the beach, but even thou
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4 years ago
How is an electron orbital similar to a parabola?
AVprozaik [17]

Answer:

Explained below.

Explanation:

First of all, the orbital path of electron is mostly parabolic in electric field.

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3 years ago
A _____ works by lighting the slide containing the specimen from below with a light bulb.
lesya692 [45]
Condenser Lens - This lens system is located immediately under the stage and focuses the light on the specimen.
5 0
3 years ago
A gas-filled balloon having a volume of 3.50 L at 1.20 atm and 18°C is allowed to rise to the stratosphere (about 30 km above th
kolezko [41]

Answer:

620.71 L the final volume of the balloon.

Explanation:

Initial volume of the gas in the balloon= V_1=3.50 L

Initial pressure of the gas in the balloon= P_1=1.20 atm

Initial temperature of the gas in the balloon= T_1=18^oC =291.15 K

Moles of gases = n

n=\frac{P_1V_1}{RT_1}...[1]

Final volume of the gas in the balloon = V_2=3.50 L

Final pressure of the gas in the balloon = P_2=5.70\times 10^{-3} atm

Final temperature of the gas in the balloon = T_2=-45^oC =228.15 K

Moles of gases = n

n=\frac{P_2V_2}{RT_2}...[2]

[1]  =  [2]

\frac{P_2V_2}{RT_2}=\frac{P_1V_1}{RT_1}

V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}

V_2=\frac{1.29 atm \times 3.50 L\times 228.15 K}{5.70\times 10^{-3} atm\times 291.15 K}=620.71 L

620.71 L the final volume of the balloon.

5 0
4 years ago
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