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GrogVix [38]
3 years ago
11

Write the point-slope form of the line that passes through (–7, 8) and has a slope of –5.

Mathematics
1 answer:
artcher [175]3 years ago
3 0

Answer: y = -5x + 20

Step-by-step explanation:

Remember that : y=mx+b

y = (-5)x + b

Now you can plug your coordinates (-7,8) into that equation.

8 = (-5)-7 + b

Solve for b

8 = -12 + b

Add +12 to both sides of your equation:

20 = b

Now, your new equation is:

y = -5x + 20

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max2010maxim [7]

The correct answer is 4737768399700 Hope this helps!

5 0
4 years ago
Read 2 more answers
Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

a\cdot b=0

By using the property

(u+v)\cdot (u-v)=0

We know that

(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2

\mid u\mid ^2-\mid v\mid^2=0

\mid u\mid^2=\mid v\mid^2

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

\mid u\mid=\mid v\mid

Hence, the length of vectors u and v must have the same length.

5 0
4 years ago
the length of a rectangle is 4/5 feet the width is 5/8 feet how much greater is the length of a rectangle than the width
Eva8 [605]
4/5(8)= 32/40
5/8(5)= 25/40
You have to get the same denominator to be able to subtract so multiply one fractions denominator by the other so it becomes the same, and vise versa.
32/40-25/40= 7/40 which cannot be simplified.
Answer= 7/40 greater than the width.
3 0
4 years ago
you provide a dog walking service, and you report to the owner the amount of exercise their dogs get on the walks. You walk BP f
notka56 [123]
1.5 miles
------------- = 2.57 mph
35/60 hr
5 0
3 years ago
If an average car is about 16 feet long, about how many car lengths should you have between you and that car in front of you if
Elden [556K]

Answer: 9 cars.

Step-by-step explanation:

given data:

average length of a car = 16feet

speed of the driver = 100miles/hr

Solution:

First we would need to convert the Speed of the car from miles/hr to Feet/secs.

To do this we know that 1mile/hr = 1.467 feet/secs

= 100m/hr * 1.467

= 146.7Feet/secs.

So now the number of cars between him would be

= 146.7Feet/secs / 16

= 9.17

approximately there should be 9 cars between you.

3 0
4 years ago
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