Answer:
Option (3)
Step-by-step explanation:
Glide reflection of a figure is defined by the translation and reflection across a line.
To understand the glide rule in the figure attached we will take a point A.
Coordinates of the points A and A' are (2, -1) and (-2, 4).
Translation of pint A by 5 units upwards,
Rule to be followed,
A(x, y) → A"[x, (y + 5)]
A(2, -1) → A"(2, 4)
Followed by the reflection across y-axis,
Rule to be followed,
A"(x, y) → A'(-x, y)
A"(2, 4) → A'(-2, 4)
Therefore, by combining these rules in this glide reflections of point A we get the coordinates of the point point A'.
Option (3) will be the answer.
Answer:
18.4°
Step-by-step explanation:
Use law of cosine.
a² = b² + c² − 2bc cos A
11² = 20² + 28² − 2(20)(28) cos A
121 = 1184 − 1120 cos A
cos A = 0.949
A = 18.4°
Answer:
here you go...
A line code is a code used to transmit digital signal data over a transmission line. Common line encodings are unipolar, polar, bipolar, and Manchester code. NonReturn-to-Zero NRZ and Return-to-Zero technologies are used in unipolar, polar, and bipolar line coding schemes. Line coding is used to reduce bandwidth, reduce the chance of error, and increase efficiency. The purpose of this lab is to understand different types of row encoding, use MATLAB to implement row encoding functions, and use the input data to simulate those row encoding functions.
hope this helps
please amrk brainiest
Dang this is too much to read i nearly understand the question
Answer is provided in the image attached.
