Which options identify what the arrows in the diagram
1 answer:
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Answer:
[H₂] = 1.61x10⁻³ M
Explanation:
2H₂S(g) ⇋ 2H₂(g) + S₂(g)
Kc = 9.30x10⁻⁸ =
First we <u>calculate the initial concentration</u>:
0.45 molH₂S / 3.0L = 0.15 M
The concentrations at equilibrium would be:
[H₂S] = 0.15 - 2x
[H₂] = 2x
[S₂] = x
We <u>put the data in the Kc expression and solve for x</u>:
We make a simplification because x<<< 0.0225:
x = 8.058x10⁻⁴
[H₂] = 2*x = 1.61x10⁻³ M
Answer:
<h2>D) 6</h2>Explanation:
since, n = molar mass / empirical formula mass
Empirical formula mass = Total mass of atoms present in empirical formula
CHCl = 12+1+35.5
= 48.5
Given, Molar mass = 290.8 g.
So, n = 290.8/48.5
= 5.995 , that is approx 6.
So, Molecular formula = n × Empirical formula
= 6 × CHCl
=
So, Number of C = 6