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solniwko [45]
2 years ago
15

Which options identify what the arrows in the diagram

Chemistry
1 answer:
Stolb23 [73]2 years ago
8 0

Answer:

D

Explanation:

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The molecule NH3 contains all single bonds.<br><br> true <br> false
dsp73
<h3><u>Answer;</u></h3>

True

<h3><u>Explanation</u>;</h3>
  • The molecule NH3 contains all single bonds.
  • NH3 has a three single covalent  bond among its nitrogen and hydrogen atoms,because one valence electron of each of three atom of hydrogen is shared with three electron.
  • There are three covalent bonds are in NH3 . Each hydrogen make a single bond with nitrogen and there is also a pair of electron which is unpaired from nitrogen.
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3 years ago
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Plz help quick
vovangra [49]

Answer:

3

Explanation:

If oxygen reacts with iron, then both must be reactants and rust the product of that reaction

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3 years ago
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As you move left to right across a period, which of the following always increases?
Artist 52 [7]

Answer:

she'll number

Explanation:

cause thats the only one

7 0
3 years ago
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Which of the following is a component of cell theory that is supported by the diagram
Crazy boy [7]
The one on top is corrrect because the cell diagram will always contain one object or more
8 0
3 years ago
Without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the follo
siniylev [52]

Answer:

∆H > 0

∆Srxn <0

∆G >0

∆Suniverse <0

Explanation:

We are informed that the reaction is endothermic. An endothermic reaction is one in which energy is absorbed hence ∆H is positive at all temperatures.

Similarly, absorption of energy leads to a decrease in entropy of the reaction system. Hence the change in entropy of the reaction ∆Sreaction is negative at all temperatures.

The change in free energy for the reaction is positive at all temperatures since ∆S reaction is negative then from ∆G= ∆H - T∆S, we see that given the positive value of ∆H, ∆G must always return a positive value at all temperatures.

Since entropy of the surrounding= - ∆H/T, given that ∆H is positive, ∆S surrounding will be negative at all temperatures. This is so because an endothermic reaction causes the surrounding to cool down.

3 0
3 years ago
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