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Mice21 [21]
3 years ago
12

Two in-phase loudspeakers are 3.0 m apart. they emit sound with a frequency of 490 hz. a microphone is placed half-way between t

he speakers and then moved along the line joining the two speakers until the first point of constructive interference is found. at what distance from that midpoint is that first point? the speed of sound in air is 343 m/s.
Physics
1 answer:
stira [4]3 years ago
3 0

Answer:

0.35 m

Explanation:

Constructive interference occurs when the difference in the distance between the two speakers is  

0, λ, 2λ,...  

Here λ = v/f = 343/490 = 0.7m  

The first point of interference is the initial point which would mean the distance is the trivial solution of 0  .

A microphone is placed half-way between the speakers and then moved along the line joining the two speakers until the first point of constructive interference is found.

Let x be the distance from the midpoint to the next interference.  

This occurs when 1.5 + x -(1.5 - x) = 0.7

so 2x = 0.7 which means x = 0.7/2 = 0.35m

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The coefficient of performance of a residential heat pump is 1.6. Calculate the heating effect in kJ/s this heat pump will produ
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✓QH=The rate at which heat is produced = ?

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7 0
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A certain unfiltered full-wave rectifier with 120 V, 60 Hz input produces an output with a peak of 15 V. When a capacitor-input
KATRIN_1 [288]

Answer:

The peak-to-peak ripple voltage = 2V

Explanation:

120V and 60 Hz is the input of an unfiltered full-wave rectifier

Peak value of  output voltage = 15V

load connected = 1.0kV

dc output voltage = 14V

dc value of the output voltage of capacitor-input filter

where

V(dc value of output voltage) represent V₀

V(peak value of output voltage) represent V₁

V₀ = 1 - ( \frac{1}{2fRC})V₁

make C the subject of formula

V₀/V₁ = 1 - (1 / 2fRC)

1 / 2fRC = 1 - (v₀/V₁)

C = 2fR ((1 - (v₀/V₁))⁻¹

Substitute  for,

f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V

C = 2 * 240 * 1 (( 1 - (14/15))⁻¹

C = 62.2μf

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The peak-to-peak ripple voltage = 2V

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