Answer:
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Explanation:
Total force required = Mass x Acceleration,
F = ma
Here we need to consider the system as combine, total mass need to be considered.
Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg
We need to accelerate the group of rocks from the road at 0.250 m/s²
That is acceleration, a = 0.250 m/s²
Force required, F = ma = 1744 x 0.25 = 436 N
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Answer:
-2.63 Joules
2.63 Joules
Explanation:
= Initial compression = 5.89 cm
= Final compression = -15.4 cm
k = Spring constant = 260 Nm
Work done by a spring is given by

Work done by the spring is -2.63 Joules.
Change in kinetic energy is given by

Here, it is assumed that change in kinetic energy is zero as velocity and amlitude are not mentioned.
So,

The work done by the applied force is 2.63 Joules.
Answer:
As the main sequence star glows, hydrogen in its core is converted into helium by nuclear fusion. When the hydrogen supply in the core begins to run out, and the star is no longer generating heat by nuclear fusion, the core becomes unstable and contracts
Explanation:
Work = (force) x (distance)
You could look at the two cases, and see right away that
the first one has more force acting through more distance,
so it must be more work. But since I just gave you the formula
for Work, let's calculate the amount of it for both cases:
First case: Work = (115 N) x (15 m) = 1,725 joules
Second case: Work = (20 N) x (10 m) = 200 joules
The first case involves 8.625 times as much work as the second case.
Both valves are closed during the power stroke.
While the fuel is burning in the cylinder, you want
all the force of the expanding gases to push the
piston down ... you don't want any of the gases
or their pressure escaping.
If either of the valves was open, even just a crack,
then part of the gases would go blooey out the valve,
and some pressure would be lost that's supposed to be
pushing the piston.