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3 years ago

The net force experienced by an object is increased. What affect does this have on the acceleration of the object?

Physics

1 answer:

Evgesh-ka [11]3 years ago

6 0

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

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When an objects total mechanical energy is conserved and it is dropped from rest how does the objects initial potential energy c

frozen [14]

Answer:Magnitude of potential energy before falling will be equal to the magnitude of the final kinetic energy, energy is only converted from potential to kinetic

Explanation: law of conservation of energy says that energy can neither be created or destroyed but Change from one form to another.so nothing will happen to the size of the potential energy when it changes to kinetic energy

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3 years ago

A wooden cylinder of length L and cross-sectional area A is partially submerged in a liquid with the axis of the cylinder orient

SCORPION-xisa [38]

Answer:

$F=\rho_LAdg$

Explanation:

The buoyant force F is equal to the weight of the displaced fluid. The weight of the displaced fluid is $W=m_dg$ , where $m_d$ is the mass of the displaced fluid. The mass of the displaced fluid is $m_d=\rho_LV_d$ , where $\rho_L$ is the density of the fluid and $V_d$ is the displaced volume, which is equal to the submerged volume of the cilinder $V_d=V_s=Ad$ .

Putting all together we have:

$F=W=m_dg=\rho_LV_dg=\rho_LAdg$

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3 years ago

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is

Arlecino [84]

Answer:

a) $v=0.5405\ m.s^{-1}$

b) $v_p'=0.1143\ m.s^{-1}$

Explanation:

Given:

mass of ball, $m_b=4\ kg$

initial speed of the ball, $v_b=10\ m.s^{-1}$

mass of the person, $m_p=70\ kg$

Using the conservation of linear momentum:

When the person catches the ball, assuming that the person catches it with an impact without absorbing the shock.

$m_b.v_b=(m_b+m_p)v$

$4\times 10=(4+70)\times v$

$v=0.5405\ m.s^{-1}$

When the ball hits the person and bounces off with the velocity of $v_b'=8\ m.s^{-1}$ .

Using the conservation of linear momentum:

$m_b.v_b+m_p.v_p=m_b.v_b'+m_p.v_p'$

where:

$v_b'=$ final speed of the ball after collision

$v_p'=$ final speed of the person after collision

$v_p=$ initial velocity of the person = 0

putting the respective values in the above eq.

$4\times 10+0=4\times 8+70\times v_p'$

$v_p'=0.1143\ m.s^{-1}$

8 0

3 years ago

Read 2 more answers

How far did the object travel by the end of eight seconds, according to the graph above?

Ulleksa [173]

Answer:

<em>The object traveled 4 cm by the end of eight seconds.</em> Correct: A)

Explanation:

<u>Speed vs Time Graph</u>

In a speed-time graph, speed is plotted on the vertical axis and time is plotted on the horizontal axis. If the graph is a horizontal line, the speed is constant, if the line is sloped up, the speed is increasing and the acceleration is positive and constant, and if the line is sloped down, the speed is decreasing and the acceleration is negative and constant.

The distance traveled by the object can be found by calculating the area under the graph and above the x-axis.

The graph provided shows two different zones: the first 4 seconds, the speed is constant at 1 cm/s, and the last 4 seconds, the speed is zero, i.e. the object is not moving.

The area behind the first zone is a rectangle of height 1 cm/s and base 4 sec, thus the distance is 1 * 4 = 4 centimeters.

The second zone corresponds to an object at rest, thus no distance is traveled.

The object traveled 4 cm by the end of eight seconds.

A) Correct. As shown above

B) The distance traveled is 4 cm. Incorrect

C) The distance traveled is 4 cm. Incorrect

D) The distance traveled is 4 cm. Incorrect

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3 years ago

A sound wave has a frequency of 265 hz and a wavelength measured at 1.3

pochemuha

Answer:

V = f λ speed of wave in terms of frequency and wavelength

t = S / V time for wave to travel a distance S

t = 91.4 m / 344.5 m/s = .265 sec time to travel 91.4 m

8 0

2 years ago