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FromTheMoon [43]
1 year ago
6

6. A tire 0.500 m in radius rotates at a constant rate of 300 revolutions per minute. Find the speed and acceleration of a small

stone lodged in the tread of the tire (on its outer edge).
Physics
1 answer:
Virty [35]1 year ago
6 0

The speed and acceleration of the stone is 15.7 m/s and 31.4 m/s^{2}.

<h3>What is acceleration?</h3>

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

<h3>Calculation of the speed of stone lodged in the tread of the tire:</h3>

Given, radius of tire (r) = 0.500 m

<h3 />

V_{t} =\frac{2\pi r}{T} \\=\frac{2\pi (0.500)}{(60s/300rev)}

= 15.7 m/s

<h3>Calculation of it's acceleration:</h3>

a=\frac{v^{2} }{R}\\\\\= \frac{15.7}{0.500}

= 31.4 m/s^{2} inward

Hence, the speed and acceleration of the stone is 15.7 m/s and 31.4 m/s^{2}

Learn more about velocity here:

brainly.com/question/18084516

#SPJ4

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Which type of exercise is weightlifting?
MatroZZZ [7]

The answer is option B "anaerobic." Weightlifting deals with stress to the muscles when lifting weights and due time the muscles will begin to adapt and get stronger. Other examples of anaerobic exercise are things like: weight training, sprinting, cycling, and jumping anything that has short exertion, and high-intensity movement is an anaerobic exercise.

Hope this helps!

Nonportrit

5 0
3 years ago
Read 2 more answers
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 45.
SpyIntel [72]

Answer:

Torque on the rocket will be 1.11475 N -m

Explanation:

We have given that muscles generate a force of 45.5 N

So force F = 45.5 N

This force acts on the is acting on the effective lever arm of 2.45 cm

So length of the lever arm d = 2.45 cm = 0.0245 m

We have to find torque

We know that torque is given by \tau =F\times d=45.5\times 0.0245=1.11475N-m

So torque on the rocket will be 1.11475 N -m

3 0
3 years ago
Active immunity is passed on from a mother to her baby.
viva [34]
True.The immune system in babies. Antibodies are passed from mother to baby through the placenta during the last three months of pregnancy.
3 0
2 years ago
If we start with 1.000 g of cobalt-60, 0.675 g will remain after 3.00 yr. this means that the of is _____
Tju [1.3M]
<span>Cobalt-60 is undergoing a radioactivity decay.

The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span>           n </span>⇒ remaining mass of cobalt after 3 years
          T ⇒ decaying period
           t ⇒ half-life of cobalt.

So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
 3/t= 0.567

t = 3÷0.567
  = 5.290626524

the half-life of Cobalt-60 is 5.29 years. 

<span>           
</span><span>
</span>
8 0
2 years ago
A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in
Kryger [21]

The average power is 3.0\cdot 10^6 W

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where :

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

m = 2000 kg is the mass of the car

v = 60 m/s is the final speed of the car

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

u = 30 m/s is initial speed of the car

Soolving:

W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J

Now we can find the power required for the acceleration, which is given by

P=\frac{W}{t}

where

t = 9 s is the time elapsed

Solving:

P=\frac{2.7\cdot 10^6}{9}=3.0\cdot 10^6 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

8 0
3 years ago
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