Answer:
Explanation:
mass of ball, m = 0.4 kg
initial velocity of ball, u = 10 m/s
your mass, M = 70 kg
your initial velocity, U = 0 m/s
(a)
As there is no external force is applied so the linear momentum of the ball and you is conserved.
Let the final velocity of ball and you is V.
So,
Initial Momentum of ball = final momentum of ball and you
m x u = ( M + m) V
0.4 x 10 = ( 70 + 0.4) x V
4 = 70.4 V
V = 0.057 m/s
Thus, your speed is 0.057 m/s after catching the ball.
(b) v' = - 8 m/s
Let V' is the final velocity of you.
Momentum of system before collision = Momentum of system after collision
( 70 + 0.4) x V = m x v' + M x V'
70.4 x 0.045 = - 0.4 x 8 + 70 x V'
4 = - 3.2 + 70 V'
V' = 0.1 m/s
Thus, your speed is 0.1 m/s towards right after hitting by the ball.