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hjlf
3 years ago
10

Lab: Acids and Bases Assignment: Lab Report

Chemistry
2 answers:
grigory [225]3 years ago
7 0

Answer:

anyone know the section II answers for a lab like this but its the thermal energy transfer lab

Explanation:

^^

Annette [7]3 years ago
5 0

Answer:

Lab: Acids and Bases Assignment: Lab Report

  • The main point is to help the scientific method and to also see how it works.
  • Sometimes people refer to the tentative answer as "an educated guess." Keep in mind, though, that the hypothesis also has to be testable since the next step is to do an experiment to determine whether or not the hypothesis is right! A hypothesis leads to one or more predictions that can be tested by experimenting.
  • <em>></em><em>State the hypotheses</em>. Every hypothesis test requires the analyst to state a null hypothesis and an alternative hypothesis. The hypotheses are stated in such a way that they are mutually exclusive. That is, if one is true, the other must be false; and vice versa.>Formulate<em> an analysis plan.</em> The analysis plan describes how to use sample data to accept or reject the null hypothesis. It should specify the following elements<em>.</em><em>></em><em>Analyze</em><em> sample data</em><em>.</em>Using sample data, perform computations called for in the analysis plan.>Interpret<em> the results.</em> If the sample findings are unlikely, given the null hypothesis, the researcher rejects the null hypothesis. Typically, this involves comparing the P-value to the significance level, and rejecting the null hypothesis when the P-value is less than the significance level and etc.

Section II: Data and Observations

  • In a lab guide, the key results are those that support my working hypotheses or serve to reject these assumptions. Moreover, the key results may also be other discoveries that are important to understand the processes and/or mechanisms investigated in the experiment.

•?

Section III: Analysis and Discussion

  • Key Results are the measures and milestones that indicate how you know you will accomplish our Objective.
  • A linear pattern is a continuous decrease or increase in numbers over time. On a graph, this data appears as a straight line angled diagonally up or down (the angle may be steep or shallow). So the trend either can be upward or downward.
  • Yes, i was surprised and learn so much and it was no problem.

Section IV: Conclusions

  • Results will tell you which hypothesis is true.
  • describe specific part of the procedure.
  • If I were able to repeat the lab and do it differently I would try to do two different things to improve it. I would try to create the model in a simpler manner that allowed me to better see how the erosion factored in. I would also try to take more detailed notes on it if I were to repeat it.
<h3 /><h3>i hope it's help</h3>
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How many grams of copper (I) chloride can be produced from the reaction of 73.5 g of copper (I) oxide with hydrochloric acid acc
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The balanced equation for the reaction is as follows

Cu₂O + 2HCl ---> 2CuCl + H₂O

Molar ratio of Cu₂O to CuCl is 1:2

mass of Cu₂O reacted - 73.5 g

Number of moles of Cu₂O reacted - 73.5 g / 143 g/mol = 0.51 mol

According to the molar ratio,

when 1 mol of  Cu₂O reacts then 2 mol of CuCl is formed

therefore when 0.51 mol of Cu₂O reacts then - 2 x 0.51 mol of CuCl is formed

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(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of
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Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

P x V = k

Therefore, for this problem the step by step explanation is:

P_{1} xV_{1} = P_{2} xV_{2}

Clearing P2 and replacing

P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm

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