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Kobotan [32]
3 years ago
12

If a sealed syringe that contains some gas is plunged into cold water, in which direction will the syringe piston slide?

Chemistry
2 answers:
s344n2d4d5 [400]3 years ago
7 0

Answer:  Syringe piston will slide down .

Explanation:  If  a sealed syringe that contains some gas is plunged unto cold water, now the gas will also gets cool by the effect of cold water.

As the cold gas has a tendency to occupy the less volume, thus making the syringe to move down.

Thus the direction of the syringe piston will be downwards making the way for the cold gas to occupy the lesser volume.

Anton [14]3 years ago
3 0
If the piston is facing towards the bottom of the container holding the cold water, the piston will not move. It will move wherever it is facing.
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In the equation N2 + 3H2 --> 2NH3, the coefficient of the hydrogen reactant is
Anastasy [175]

Explanation:

the coefficient of hydrogen is 3

8 0
3 years ago
A sample of an unknown gas occupies 5.51 L at 1.31 atm. What pressure would thisgas exert in a 0.520 L container if the temperat
weeeeeb [17]

Answer:

P₂ = 13.9 atm (3 sig. figs.)

Explanation:

The pressure (P), Volume (V) relationship with Temperature (T) & mass (n) held constant is an inverse proportionality. That is Boyles Law ...

P ∝ 1/V => P = k/V => k = P·V

For two pressure-volume conditions, the proportionality constant (k) remains constant where k₁ = k₂ and P₁·V₁ = P₂·V₂ => P₂ = P₁·V₁/V₂

Given:

P₁ = 1.31 atm.

V₁ = 5.51 L

P₂ = ?

V₂ = 0.520 L

V₂ = (1.31 atm)(5.51L)/(0.520L) = 13.88096154 atm (calc. ans.) = 13.9 atm (3 sig. figs.)

5 0
3 years ago
Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Brz(9) 2NOBr(g) A reaction mixture was found to contain 2.69x1
bekas [8.4K]

Explanation:

2NO(g) + Br_2(g)\rightleftharpoons 2NOBr(g)

Equilibrium constant of reaction = K=154

Concentration of NO = [NO]=\frac{2.69\times 10^{-2} mol}{1 L}=2.69\times 10^{-2} M

Concentration of bromine gas = [Br_2]=\frac{3.85\times 10^{-2} mol}{1 L}=3.85\times 10^{-2} M

Concentration of NOBr gas = [Br_2]=\frac{9.56\times 10^{-2} mol}{1 L}=9.56\times 10^{-2} M

The reaction quotient is given as:

Q=\frac{[NOBr]^2}{[NO]^2[Br_2]}=\frac{(9.56\times 10^{-2} M)^2}{(2.69\times 10^{-2} M)^2\times 3.85\times 10^{-2} M}

Q=328.06

Q>K

The reaction will go in backward direction in order to achieve an equilibrium state.

1. In order to reach equilibrium NOBr (g) must be produced.  False

2. In order to reach equilibrium K must decrease. False

3. In order to reach equilibrium NO must be produced. True

4. Q. is less than K . False

5. The reaction is at equilibrium. No further reaction will occur. False

8 0
2 years ago
2N2O(g) +3O2(g) 4NO2(g). Which equilibrium expression is correct?
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<span>Kc = [NO2]^4 / [N2O]^2[O2]^3</span>
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I will give brainliest to correct answer - no links
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Answer:

C - 23cm

Explanation:

6 0
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