The rate of movement increases, as they get faster with more energy.
Answer:Since 1743 the Celsius scale has been based on 0 °C for the freezing point of water and 100 °C for the boiling point of water at 1 atm pressure. Prior to 1743 the values were reversed (i.e. the boiling point was 0 degrees and the freezing point was 100 degrees).
Explanation: i no it
Answer:
Explanation:
Since the temperature is held constant, we only need to focus on the volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula is:
Originally, the gas had a volume of 150 milliliters and a pressure of 3.0 atmospheres. We can substitute these values into the left side of the equation.
The original gas was compressed to a volume of 50 milliliters, but we don't know the volume.
Now, we need to solve for the new pressure (P₂). Multiply on the left side first.
Since we are solving for the pressure, we need to isolate the variable. It is being multiplied by 50 mL. The inverse of multiplication is division. Divide both sides by 50 mL.
The units of milliliters will cancel.
The new pressure is <u>9 atmospheres.</u>
Heat energy is supplied to materials and can cause an increase in temperature of the material. the formula is as follows
H = mcΔt
where H - heat energy
m - mass of material
c - specific heat
Δt - change in temperature - 40.0 °C - 22.5 °C = 17.5 °C
substituting the values
H = 175 g x 0.234 Jg⁻¹°C⁻¹ x 17.5 °C
H = 716.6 J
716.6 J is required
Answer:
1550.8
Explanation:
This is the ideal gas equation:
PV=nRT
We can rearrange the ideal gas equation to solve for the pressure of the nitrogen gas.
P=nRT/ V
We can find the pressure of the nitrogen gas by plugging in the values for the moles of gas, temperature, and volume. Since we want the pressure in units of Torr we use the R value62.36358L Torr K−1 mol-1
P=nRT/ V
(0.316 mol )(62.36358 L*Torr/K*mol)(315 K) / 4.00 L =1550 Torr
The correct answer is 1550
