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3 years ago

When 8.30 mol Mg react with 13.5 mol HCI, what is the limiting reactant and how many moles of H2 can be formed?

Chemistry

1 answer:

vovikov84 [41]3 years ago

4 0

6.75 moles of H₂

Explanation:

We have the following balanced chemical reaction:

Mg + 2 HCl → MgCl₂ + H₂

From the chemical reaction we deduce that if 1 mole of Mg is reating with 2 moles of HCl then 8.30 moles of Mg is reaction with 16.60 moles of HCl, quantity which is over our available 13.5 moles of HCl. The limiting reactant is HCl.

Knowing this we devise the following reasoning:

if 2 moles of HCl produces 1 mole of H₂

then 13.5 moles of HCl produces X moles of H₂

X = (13.5 × 1) / 2 = 6.75 moles of H₂

Learn more about:

balancing chemical equations

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A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate

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Step 2: Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

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