Question

When 8.30 mol Mg react with 13.5 mol HCI, what is the limiting reactant and how many moles of H2 can be formed?

Answer 1

6.75 moles of H₂

Explanation:

We have the following balanced chemical reaction:

Mg + 2 HCl → MgCl₂ + H₂

From the chemical reaction we deduce that if 1 mole of Mg is reating with 2 moles of HCl then 8.30 moles of Mg is reaction with 16.60 moles of HCl, quantity which is over our available 13.5 moles of HCl. The limiting reactant is HCl.

Knowing this we devise the following reasoning:

if         2 moles of HCl produces 1 mole of  H₂

then    13.5 moles of HCl produces X moles of  H₂

X = (13.5 × 1) / 2 = 6.75 moles of H₂

Learn more about:

balancing chemical equations

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