All categories

3 years ago

An automobile accelerates from rest at 1+ 3* sqrt (t) mph/sec for 9 seconds.

1 answer:

3 0

Writing the acceleration as a function of time:
a(t) = 1 + 3√t

Integrating acceleration, we obtain velocity:
v(t) = t + 2(t)^(3/2) + c;
object at rest so velocity at t = 0 is 0 so c = 0.
v(t) = t + 2(t)^(3/2)

Integrating velocity to obtain an equation for displacement:
d(t) = t²/2 + 4/5 t^(5/2) + c
Applying limits from t = 0 to t = 9
d = 9²/2 + 4/5 9^(5/2)
d = 234.9 m

You might be interested in

A 1.0-kg object moving in a certain direction has a kinetic energy of 2.0 J. It hits a wall and comes back with half its origina

saw5 [17]

Lets calculate the initial speed of the block. We know that kinetic energy is given by:

$K_0 =\dfrac{mv_0^2}{2}$

Solving for v₀:

$v_0 = \sqrt{ \dfrac{2K_0}{m}} = \sqrt{ \dfrac{2(2\;J)}{1\;kg}} = 2\;m/s$

If the speed after it hits a wall is half its original speed then:

v = v₀/2 = 2 m/s / 2 = 1 m/s

Then the kinetic energy at this point is:

$K =\dfrac{mv^2}{2} = \dfrac{(1\;kg)(1\;m/s)^2}{2} = \dfrac{1}{2}\;J = 0.5\;J$

The inetic energy of this object at this point is 0.5 J.

5 0

3 years ago

A 2000 kg test car travels around a circular track with a radius of 100 m. If the

Anarel [89]

Answer:

V=0.38 m/s

Explanation:

ac=3 m/s^2

m=2000kg

r=100m

ac=mv^2/r

Solve for v^2

3=2000(v^2)/100

3=20v^2

3/20=.15

sqrt of .15= 0.38 m/s

V=0.38 m/s

6 0

3 years ago

What can you use to stick blocks of snow together answer sheet?

solong [7]

Answer: you can use salt and a bit of heat the

Explanation:put salt on the place you want it to stick then heat it up a littel and it should freeze together

5 0

4 years ago

A proton starting from rest travels through a potential of 1.0 kV and then moves into a uniform 0.040-T magnetic field directed

Hatshy [7]

Answer:

0.114m

Explanation:

From the general expression for the radius of the proton's resulting orbit, we have

$r=\frac{mv}{qB}$

where q is is the charge of the proton $1.6*10^{-19}C$

m is the mass of the proton $1.67*10^{-27}kg$

B is the magnetic field $0.040T$

and v i the speed.

to determine the speed, we use the expression

Kinetic Energy= $qV$

$1/2mv^{2}=qV$

where <em>V </em>is the voltage value i.e 1.0kv

and v is the speed

Hence, from simple rearrangement we have the speed v to be

$v=\sqrt{\frac{2Vq}{m}} \\$

if we substitute value, we have

$v=\sqrt{\frac{2*1000*1.6*10^{-19} }{1.67*10^{-27}}} \\$

carrying out careful arithmetic we arrive at

$v=4.38*10^{5} m/s$ .

using the value for the speed in the expression for the radius of the orbit as stated earlier, we have

$r=\frac{1.67*10^{-27}*4.38*10^{5}}{1.6*10^{-19}*0.04} \\$

$r=0.114m$

7 0

3 years ago

In an electrically neutral atom of any element, there are equal numbers of

Alinara [238K]

Answer:

B) Electrons and protons

Explanation:

Each proton has a positive charge, and each electron has a negative charge. If the atom is electrically neutral, there must be the same number of electrons and protons.

A) and C) are wrong. Neutrons have no charge, so they can't counteract that of the protons or the electrons.

D) is wrong. The atomic number is the number of protons, and the mass number is the number of protons plus neutrons. The neutrons can't counteract the charge of the protons,

4 0

3 years ago