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4 years ago

7

What do lenses do?

2 answers:

Dovator [93]4 years ago

3 0

A convex lens makes light rays converge (come together) at the focal point or focus. The distance from the center of the lens to the focal point is the focal length of the lens. Convex lenses are used in things like telescopes and binoculars to bring distant light rays to a focus in your eyes.

strojnjashka [21]4 years ago

3 0

B:refract light when a focused beam of light hits the lens it splits apart into smaller beams

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A kid is on a stationary sled, on

gregori [183]

The mass of the kid and the sled is 50.0 kg

Explanation:

The sled starts to move when the force applied becomes larger than the maximum force of static friction, which is given by

$F_{max} = \mu_s mg$

where

$\mu_s$ is the coefficient of static friction

m is the mass of the kid + the sled

$g=9.8 m/s^2$ is the acceleration of gravity

Here the sled starts moving when the force applied is 61.2 N, so

$F_{max}=61.2 N$

And we also know

$\mu_s = 0.125$

Therefore, we can find the mass of the kid and the sled by re-arranging the equation:

$m=\frac{F_{max}}{\mu_s g}=\frac{61.2}{(0.125)(9.8)}=50.0 kg$

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

6 0

4 years ago

Once Kate's kite reaches a height of 52 ft (above her hands), it rises no higher but drifts due east in a wind blowing 6 ft d

Andru [333]

Answer:

5.213ft

Explanation:

Z² = x² + y²

x = √(z² - y²)

y = 52ft, dx = 6ft, z = 105ft, dz = ?

d(z² = x² + y²)

2zdz = 2xdx

dz = xdx/z

But x = √(z² - y²)

dz = √(z² - y²)/z * dx

dz = [√(105² - 52²)/105] * 6

dz = √(8521)/ 17.5

dz = 5.213ft

7 0

3 years ago

Here is a list of ways of producing electricity

zloy xaker [14]

Answer:

1) A,B,F,G

2)B,D,E

3) A,C,F,G

Explanation:

8 0

3 years ago

A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m.

strojnjashka [21]

Answer:

$D=99.4665307m \approx 99.5m$

Explanation:

From the question we are told that

Mass $m=6kg$

Velocity of mass $V_m=16$

Force of Tunnel $F_t=8N$

Length of Tunnel $L_t=1.6$

Height of frictional incline $H_i=2.9$

Angle of inclination $\angle =16 \textdegree$

Acceleration due to gravity $g=9.8m/s^2$

First Frictional surface has a coeﬃcient $\alpha_1 =0.21\ for\ d_c=1$

Second Frictional surface has a coeﬃcient $\alpha _2=0.1$

Generally the initial Kinetic energy is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}(6)(16)^2$

$K.E=768$

Generally the work done by the Tunnel is mathematically given as

$w_t=F_t*d_t$

$w_t=8*1.6$

$w_t=12.8J$

Therefore

$Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t$

$E_t=K.E+E_t\\E_t=768J+12.8J$

$E_t=780.8J$

Generally the energy lost while climbing is mathematically given as

$E_c=mgh$

$E_c=(6)(9.8)(2.9)$

$E_c=170.52J$

Generally the energy lost to friction is mathematically given as

$E_f=\alpha *m*g*cos\textdegree*d_c$

$E_f=0.21*6*9.8*cos16*1$

$E_f=11.86965942 \approx 12J$

Generally the energy left in the form of mass $Em$ is mathematically given as

$E_m=E_t+E_c+E_f$

$E_m=(768J)-(170.52)-(12)$

$E_m=585.48J$

Since

$E_m=\alpha_2*g*m*d$

Therefore

It slide along the second frictional region

$D=\frac{585.46}{0.1*9.81*6}$

$D=99.4665307m \approx 99.5m$

6 0

3 years ago

How far does the gravitational field of Earth extend?

icang [17]

I JUST NEED POINTSSS sorry hope you do good tho!

8 0

3 years ago

Read 2 more answers