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ludmilkaskok [199]
2 years ago
13

A substance that has a pH = 7 is a/an

Chemistry
1 answer:
Len [333]2 years ago
3 0
Neutral solution, hope this helps :)
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Sergio [31]
I believe it’s the third option
Chemically combined to make a new pure substance
7 0
3 years ago
Read 2 more answers
Develop a demonstration to show how mass is not the same thing as weight
pychu [463]

This is more of a physics explanation, but here we go.

Mass is a measure of how much "matter" is in an object. Weight is the force applied onto an object by gravity. Weight itself can be related to mass like this:

f_g = mg

where g is a gravitational constant. For our purposes, it's defined by whatever planet you are on. Following this, we can demonstrate that mass is NOT the same thing as weight if we take two objects of the same mass and put them on different planets.

Let E refer to Earth and F refer to Mars

g_E = 9.81 m/s^2\\g_F = 3.711 m/s^2

Following this, we can see clearly that weight is not the same as mass:

m*9.81 : m*3.711 \\\int\limits^a_b {x} \, dx 9.81 \neq 3.711\\f_g E \neq f_g F\\

If weight was the same thing as mass, the two values would be the same, as the mass of the two objects is the same. But since weight is defined in the context of gravity, they are not.

4 0
3 years ago
Will mark the brainiest later for correct answers! Please show work.
Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

a. moles in 14.08 g of C_{12}H_{22}O_{11} = \frac{14.08g}{342.3g/mol}=0.04113moles

molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

7 0
3 years ago
An iminium ion is formed as an intermediate in a stork enamine reaction. the iminium is subsequently hydrolyzed with water. comp
Dvinal [7]
Below is the mechanism showing the hydrolysis of Iminium Ion into aldehye. The arrows are shown in RED.

7 0
2 years ago
II need this asap !!!!!!!
Xelga [282]

Answer:

1. B.10 mol/l

2. D.

3.A.

Explanation:

Totoo po yan ganyan po yong sakin

7 0
2 years ago
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