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valentina_108 [34]
3 years ago
13

What in math what does it mean when I'd a sample process is in control or not?

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0
I'm not totally sure what you are asking, but maybe this is a question about dependent and independent variables?

If so, these types of variables are used in math and science as measures. In math, independent variables and dependent variables are the "tools" used in an experiment. 

Independent variables are the variables that are controlled during the experiment. These variables do not change during the experiment.

Dependent variables are the variables whose values change based on the independent variables. These variables are the "outcome" portion. 


I have no idea if this answers your question or not. All I can say is that the "controlled" part of a sample would be the independent variable. 
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Which expression is equivalent to (3x² + 4x - 7)(x - 2)? (Apex)
katovenus [111]

Answer:

A i think

Step-by-step explanation:

3 0
3 years ago
The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun
Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. \mu=12.30 and \sigma=0.20

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process =  probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587

Hence, the required probability= A) 0.1587

6 0
3 years ago
Your welcome. enjoy ur day :)
Nat2105 [25]
Thank you!!! enjoy yours
4 0
3 years ago
Read 2 more answers
A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the grou
kotykmax [81]

Answer:

(a) The probability that his height is less than 66 inches is 0.2743.

(b) The probability that the height is between 66 and 71 inches is 0.4679.

(c) The probability that the height is more than 71 inches is 0.2578.

Step-by-step explanation:

The data given in the question is:

Mean (μ) = 68.4

Standard Deviation (σ) = 4

Let X denote the height of men. We will use the normal distribution z-score formula to calculate the z-score and then look up the probability in the normal probability distribution table. The z-score formula is:

z = (X - μ)/σ

(a) For P(X<66), first calculate the z value.

z = (66-68.4)/4

z = -0.6 (Look up this value in the standard normal distribution table)

P(z<-0.6) = 0.2743

The probability that his height is less than 66 inches is 0.2743.

(b) P(66<X<71)  = P(X<71) - P(X<66)

We need to find P(X<71) so, calculating the z-value:

z = (71-68.4)/4

z = 0.65

P(z<0.65) = 0.7422

P(66<X<71)  = 0.7422 - 0.2743

P(66<X<71)  = 0.4679

The probability that the height is between 66 and 71 inches is 0.4679.

(c) To find the probability P(X>71), we need to find P(X<71) and then subtract it from 1 because the normal distribution table gives values for P(X<k). We have already calculated the value of P(X<71) in part (b) so,

P(X>71) = 1 - P(X<71)

            = 1 - 0.7422

P(X>71) = 0.2578

The probability that the height is more than 71 inches is 0.2578.

3 0
3 years ago
Having some trouble here
icang [17]

Answer:

None of them are correct i believe

Step-by-step explanation:

its sideways lol

8 0
2 years ago
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