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amid [387]
3 years ago
13

Please don't explainn just say answer please help

Mathematics
2 answers:
White raven [17]3 years ago
5 0

Answer:

whats the original temperature it cut off, c ant answer this without seeing that

but just keep subtracting 3 from it per hour

Step-by-step explanation:

kumpel [21]3 years ago
4 0

Answer:

pick v

Step-by-step explanation:

You might be interested in
Add 7 to me. Then subtract 10. If you subtract 5 and then add 9, you get 14. What number am I?
Vesna [10]

Answer:

your answer is 13.

am I correct.

3 0
3 years ago
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
I need help, can someone please explain this step by step.
Helga [31]

180-117.3=62.7

answer is 62.7

3 0
3 years ago
Please find the missing side of this triangle
umka21 [38]

Answer:

The answer is 8.30

Step-by-step explanation:

Using cos 41 = x/11

x = cos 41 × 11

x = 8.30

4 0
3 years ago
'Five times a number minus eight is 17.5.
11Alexandr11 [23.1K]

Answer:

5.1

Step-by-step explanation:

you need to work backwards.

so do 17.5 + 8 then divide by 5 to get 5.1

i hope this helps :)

8 0
3 years ago
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