Ask question

Ask question

All categories

3 years ago

8

The population of California is approximately 38,040,000. The population of Texas is about 2.606 × 107. What is the approximate

total population of these two states?

2 answers:

Radda [10]3 years ago

8 0

Answer:

Step-by-step explanation:

California population 3.804 x10^7

texas population 2.606x 10^7

total= 6.4 x10^7

balandron [24]3 years ago

3 0

Answer:

c

Step-by-step explanation:

You might be interested in

The company financial officer was interested in the average cost of PCs that had been purchased in the past six months. She took

SpyIntel [72]

Answer:

$1,482 is the 10th percentile.

Step-by-step explanation:

xth percentile:

If a measure is said to be in the xth percentile, it means that x% of the measures are smaller than it, and (100-x)% are larger.

In this question:

10 computers, the 10th percentile is the value that is larger than 10% of the prices.

The prices, sorted in an increasing way, are:

$1,127, $1,482, ...

Computers at a price of $1,482 have larger prices than 10% of the population, so $1,482 is the 10th percentile.

6 0

3 years ago

Multiply the binomials. (3x-y)(x+2y) and (x +6)^2

Yuki888 [10]

Answer:

tt

Step-by-step explanation:

boi

8 0

3 years ago

A waiter earns $128 for 6 hours of work. The total included $86 in tips. How much does the waiter earn each hour? How would I wr

VladimirAG [237]

Answer:$7=1 hour

Step-by-step explanation:

7 0

4 years ago

A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$

And using the De Morgan laws we know that:

$(A \cap B)' = A' \cup B'$

So then we can write the probability like this:

$P(B' \cup A') = P((A \cap B)')$

And using the complement rule we can do this:

$P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)$

Since A and B are independent we have:

$P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32$

And then our final answer would be:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

5 0

3 years ago

Please help me on number 31 please I beg you

Brums [2.3K]

Assuming the garden is a rectangle, the area is equal to length times width.

So 20x = 760.

Divide both sides by 20.

x = 760/20 = 38 ft

8 0

3 years ago