HELPPPPP I WILL GIVE U THE BRAINLEST!!!!

PLEASE HELP I BEG YOU!!!! <br> Graph the linear equation.<br><br> 2x+6y=−6

Taya2010 [7]

Answer:

it will be 8xy

Step-by-step explanation:

2x+6y=-6

2x+6y=8xy

3 0

2 years ago

Read 2 more answers

In his Fourth of July speech, Douglass says that "above your national, tumultuous joy, I hear the wail of millions.” To what is

krok68 [10]

I think that what Frederick Douglass meant by the "wail of millions" is that while the 4th of July is a great day to be celebrated by non-African American people as it meant the true independence of the 13 colonies from Great Britain and freedom for many of its citizens, in fact slavery is still intact at the time of his speech in 1852 and so July 4th cannot be celebrated by the vast majority of the black people in the US who are still under the terrible yoke of slavery.

6 0

3 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(c) $\displaystyle P(B) = \frac{9}{100}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

2 years ago

The formula P = 6s gives the formula for the perimeter of a regular hexagon with side length s. What is the perimeter of a regul

stellarik [79]

YOU NEED A BETTER SCHOOL

6 0

2 years ago

How do I do 3 x 10^5

Ilya [14]

Answer: 3(10^5)

=3*10^5

=3*(10*10*10*10*10)

=300000

This is how you should do It, just when it is squared you should times the number like up here you times 10 times 10 5 times so if you see it you don't times it by 5 you do 10 times 10 times 10 times 10 times 10 like this

You should get it now

Have a good day

Yours,

Nathaniel

Step-by-step explanation:

4 0

2 years ago