3 years ago

(give the answer or I'll report) please solve it with the steps

Physics

1 answer:

Leona [35]3 years ago

3 0

Answer:

The required elastic potential energy is 0.068J

Explanation:

Given,

Spring force constant, k= 3.4 N/M

Spring stretch length/ Displacement, x= 0.2m

We know,

Elastic potential energy, V= $\frac{1}{2} kx^{2}$

= $\frac{1}{2}*3.4*(0.2)^{2}$

= $\frac{0.136}{2}$

=0.068

∴The required elastic potential energy is 0.068J

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Vanyuwa [196]

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