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vladimir2022 [97]
3 years ago
11

(give the answer or I'll report) please solve it with the steps​

Physics
1 answer:
Leona [35]3 years ago
3 0

Answer:

The required elastic potential energy is 0.068J

Explanation:

Given,

Spring force constant, k= 3.4 N/M

Spring stretch length/ Displacement, x= 0.2m

We know,

Elastic potential energy, V= \frac{1}{2} kx^{2}

                                           =\frac{1}{2}*3.4*(0.2)^{2}

                                           =\frac{0.136}{2}

                                           =0.068

∴The required elastic potential energy is 0.068J

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