All categories

3 years ago

(give the answer or I'll report) please solve it with the steps

Physics

1 answer:

Leona [35]3 years ago

3 0

Answer:

The required elastic potential energy is 0.068J

Explanation:

Given,

Spring force constant, k= 3.4 N/M

Spring stretch length/ Displacement, x= 0.2m

We know,

Elastic potential energy, V= $\frac{1}{2} kx^{2}$

= $\frac{1}{2}*3.4*(0.2)^{2}$

= $\frac{0.136}{2}$

=0.068

∴The required elastic potential energy is 0.068J

You might be interested in

Suppose that you observe light emitted from a distant star to be at a wavelength of 525 nm. The wavelength of light to an observ

Tomtit [17]

Answer:

The velocity of the star is 0.532 c.

Explanation:

Given that,

Wavelength of observer = 525 nm

Wave length of source = 950 nm

We need to calculate the velocity

If the direction is from observer to star.

From Doppler effect

$\lambda_{0}=\sqrt{\dfrac{c+v}{c-v}}\times\lambda_{s}$

Put the value into the formula

$525=\sqrt{\dfrac{c+v}{c-v}}\times950$

$\dfrac{c+v}{c-v}=(\dfrac{525}{950})^2$

$\dfrac{c+v}{c-v}=0.305$

$c+v=0.305\times(c-v)$

$v(1+0.305)=c(0.305-1)$

$v=\dfrac{0.305-1}{1+0.305}c$

$v=−0.532c$

Negative sign shows the star is moving toward the observer.

Hence, The velocity of the star is 0.532 c.

7 0

3 years ago

Which of the following is equivalent to 2.5 meters

blsea [12.9K]

B is the correct answer for sure bro

5 0

3 years ago

Read 2 more answers

Mga halimbawa ng metapora

faust18 [17]

Answer:

UMm If i understood ide answer

Explanation:

4 0

2 years ago

Read 2 more answers

A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill, starting from rest. If th

Korvikt [17]

Answer:

A(3.56m)

Explanation:

We have a conservation of energy problem here as well. Potential energy is being converted into linear kinetic energy and rotational kinetic energy.

We are given ω= 4.27rad/s, so v = ωr, which is 6.832 m/s. Place your coordinate system at top of the hill so E initial is 0.

Ef= Ug+Klin+Krot= -mgh+1/2mv^2+1/2Iω^2

Since it is a solid uniform disk I= 1/2MR^2, so Krot will be 1/4Mv^2(r^2ω^2= v^2).

Ef= -mgh+3/4mv^2

Since Ef=Ei=0

Mgh=3/4mv^2

gh=3/4v^2

h=0.75v^2/g

plug in givens to get h= 3.57m

5 0

3 years ago

easy bio A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 438 N and have a center of

goblinko [34]

Answer:

1.034 m above the floor

Explanation:

The location of center of body for a compound body, when the weights are given is calculated as:

$\bar x = \frac{W_1x_1+W_2x_2+W_3x_3+W_4x_4+W_5x_5+.......+Wnx_n}{W_1+W_2W_3W_4W_5+.....+W_n}$

where,

$\bar x$ is the center of gravity of the entire body

W = weight of the individual body

x = center of gravity of the individual body

Thus on substituting the values we get,

$\bar x = \frac{438\times 1.28+144\times 0.760+87\times 0.250}{438+144+87}$

$\bar x = \frac{691.83}{669}$

$\bar x =1.034m$

Hence, the center of gravity of the entire body lies 1.034 m above the floor

6 0

3 years ago

(give the answer or I'll report) please solve it with the steps​

(give the answer or I'll report) please solve it with the steps