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antoniya [11.8K]
1 year ago
11

Can and object have a negative position and a positive velocity? Or vice versa, a positive position and a negative velocity? Exp

lain your reasoning, do not just give a simple sentence answer.​
Physics
1 answer:
zavuch27 [327]1 year ago
4 0
Imagine a ball is moving on the following horizontal line.

. . . . . . . . . . . . . . . . . . . O. . . . . . . . . . . . . . . . . .

Take right as positive. O is the starting point of the ball. Denote the ball by o.

. . . . . . . . . . . . . . . . . . . O. . . . . . . ... . . o . . . . . .

Assume the ball is moving to the right. It has positive displacement since it is on the right of O, and positive velocity since its positive displacement is increasing.

.ñ

. . . . . . . . . . . . . . . . . . . O. . . . o . . . . . . . . . . . . .

Now the ball is returning to O. It still has positive displacement since its current position is still on the right of O. However, its velocity is negative since its positive displacement is decreasing and the direction of the velocity vector points left, which is the negative side.

By now you should be able to come up with a scenario where the ball has negative displacement and positive velocity.

You can observe the same phenomenon in daily life. Say, as a stretched spring bounces to its starting position, if we let the returning direction be positive, the string has negative displacement since it is on the negative direction, but has positive velocity. Bungee jump can also used to illustrate the phenomenon.
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What body in the solar system do you think is one focus of the moons orbit
PolarNik [594]

-- From the point of view of an observer on Earth, the moon's orbit is an ellipse
with the Earth's center at one focus.

-- From the point of view of an observer on the sun, or on any other planet,
the moon's orbit is an ellipse with the sun at one focus, and perturbed by being
near the Earth.


6 0
3 years ago
Read 2 more answers
Calculate the speed of an object that tavels 62.43m in 38.4s
TiliK225 [7]
The speed of the object can be calculated using the formula:

Speed = distance/time

The given values are:
distance = 62.43 m
time = 38.4 s

Solution:

speed = 62.43 m / 38.4 s = 1.63 m/s

Therefore, the speed of an object that travels 62.43m in 38.4s is <span> 1.63 m/s.</span>
8 0
3 years ago
An arrow of mass 415 g is shot at a target with a speed of 68.5m/s. The target, which has a mass of 3.3 kg, is moving toward the
Murrr4er [49]

The velocity of the target and arrow after collision is 6.67m/s

<u>Explanation:</u>

Given:

Mass of arrow, mₐ = 415g

Speed of arrow, vₐ = 68.5m/s

Mass of the target, mₓ = 3.3kg = 3300g

speed of the target, vₓ = -1.1m/s (Because the target moves in opposite direction

Velocity of the target and arrow after collision, vₙ = ?

Applying the conservation of momentum,

mₐvₐ + mₓvₓ = (mₐ+mₓ) vₙ

415 X 68.5 + 3300 X -1.1 = (415+3300) X vₙ

28427.5 - 3630 = 3715 X vₙ

24797.5 = 3715 X vₙ

vₙ = 6.67m/s

Therefore, the velocity of the target and arrow after collision is 6.67m/s

4 0
3 years ago
a person hears an echo from the top of a tower , 2.2 second after the sound is produced.how far away is the tower from the perso
bekas [8.4K]

Answer:

730.4 m

Explanation:

The sound waves travels with a uniform motion (=constant velocity), therefore we can calculate the distance it travels using the formula:

d=vt

where

d is the distance

v is the speed of the sound wave

t is the time taken

In this problem we have:

v = 332 m/s is the speed of sound in air

t = 2.2 s is the time elapsed

Therefore, the distance between the tower and the person is

d=(332)(2.2)=730.4 m

5 0
3 years ago
IF a car trip 400 km in four hours what is the rate of speed that a car is traveling?
Andreas93 [3]

Speed = Distance/ Time

Speed = 400 / 4

Speed = 100 km/hr.

100 km per hour.
8 0
2 years ago
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