Answer:
The concentration is [-1 + sqrt(1+0.11t)]/0.1542 M
Explanation:
Let the concentration of CH3CHO after selected reaction times be y
Rate = Ky^2 = change in concentration of CH3CHO/time
K = 0.0771 M^-1 s^-1
Change in concentration of CH3CHO = 0.358 - y
0.0771y^2 = 0.358-y/t
0.0771ty^2 = 0.358 - y
0.0771ty^2 + y - 0.358 = 0
The value of y must be positive and is obtained in terms of t using the quadratic formula
y = [-1 + sqrt(1^2 -4(0.0771t)(-0.358)]/2(0.0771) = [-1 + sqrt(1+0.11t)]/0.1542 M
Answer:
Yesssssss , option two is the correct one click it buddy
Explanation:
Answer:
from the ideal gas law, P2 /P1 = T2 /T1 for the same volume and quantity of gas. P2 = (758 mmHg) (45 +273 K) / (15 +273K) = 837 mmHg.
Explanation:
Answer:
Osmosis
Explanation:
The osmosis is a movement from somewhere with a lower concentration of a substance to somewhere with a higher concentration of the same substance. Against the concentration gradient. It occurs through a semi permeable membrane which prevents a non desired substance cross it. Also, it's very important to biological process.