Answer:
a)6.7m/S
b)6.8m/s
Explanation:
Hello ! To solve the point b you must follow the steps below
1.Draw the slide taking into account its length and height and find the angle from which the swimmer is launched (see attached image)
2. Find the horizontal velocity (X) and vertical (Y) components (see attached image)
3) for the third step we must remember that as in the slide there is no horizontal acceleration the speed in X will remain constant at the end of the swimmer's path (Vx = 0.59m / s)
4)
the fourth step is to remember that vertically there is constant acceleration called gravity (g = 9.81m / s ^ 2), so to find the speed at the end of the route we use the following equation

where
Vfy= final verticaly speed
Vy=initial verticaly speed=0.59m/S
g=gravity=9.81m/S^2
y=height of slide=2.31m
solving

The last step is to add the velocity components vectorally at the end of the route with the following equation

point A
taking into account the previous steps we can infer that as the swimmer starts from rest, the velocity (Vx=Vy=O) is zero, so we should only use the formula for constant acceleration movement.

vy=0

Vfy=
=6.7m/s
Answer:
<em>c. ABBA counterbalancing
</em>
Explanation:
The student should not use the method because it is a progressive error management technique for each subject by introducing all <em>treatment circumstances twice, first in one sequence, then in the other (AB, BA) by subject counterbalancing.</em>
If participants experience conditions more than once, they experience the conditions first in one order, then the opposite order.
If you stand up in a big room and echo, your voice will echo
from the walls. As long as the room is empty. Since
the speed of sound is constant, depending on air density, the more humid the
air the faster and farther sound travels. The
speed of sound is constant, you could measure the time it takes for your voice
to echo off the walls. The same thing happens with Doppler radar, but it’s not voice,
it has higher frequency signals.<span> </span>