Answer:
current in water = 0.924 A
Explanation:
Let the current in each row be i.
Thus, current in water is contributed by each row and total current in water becomes 140i.
We are given;
emf of each electroplaque = 0.15 V
Number of electroplaques = 5000
internal resistance = 0.25 Ω
resistance = 800Ω
Applying Kirchoff's Voltage Law to row and water, we have;
5000E − (5000r)i − 800(140i) = 0
Rearranging;
5000E = (5000r)i + 800(140i)
Plugging in the relevant values;
5000 x 0.15 = i((5000 x 0.25) + 112,000)
750 = 113,250i
i = 750/113,250
i = 0.0066 A
Recall earlier, the current in water is 140i.
Thus, current in water = 140 x 0.0066
= 0.924
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