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Nataly [62]
3 years ago
12

You find a piece of iron with a density of 10.4g/cm3. Which layer of the earth might it come from

Physics
1 answer:
topjm [15]3 years ago
3 0

Answer:

the inner core if I believe. I apologize if I am incorrect

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Which of the following statements is true?
Alborosie
My guess is A. I'm not 100% positive but i'm pretty sure.
8 0
3 years ago
It takes 9 sec for a 10 newton force to move an object 4 meters to the right. What is direction & magnitude of the force
lana66690 [7]

Answer:

the question is wrong

Explanation:

  1. M is not given
  2. after 9 second the acceleration multiply by the time divided by two then multiplied by the time is equal to 4 meter
  3. ((10/Mm/s *9s-)
3 0
3 years ago
A particle moves at a constant speed in a circular path with a radius of r=2.06 cm. If the particle makes four revolutions each
nataly862011 [7]

The centripetal acceleration is 13.0 m/s^2

Explanation:

For an object in uniform circular motion, the centripetal acceleration is given by

a=\frac{v^2}{r}

where

v is the speed of the object

r is the radius of the circle

The speed of the object is equal to the ratio between the length of the circumference (2\pi r) and the period of revolution (T), so it can be rewritten as

v=\frac{2\pi r}{T}

Therefore we can rewrite the acceleration as

a=\frac{4\pi^2 r}{T^2}

For the particle in this problem,

r = 2.06 cm = 0.0206 m

While it makes 4 revolutions each second, so the period is

T=\frac{1}{4}s = 0.25 s

Substituting into the equation, we find the acceleration:

a=\frac{4\pi^2 (0.0206)}{0.25^2}=13.0 m/s^2

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

8 0
3 years ago
The tundra is located _______.
Leona [35]

Answer:

d: both north and south

Explanation:

8 0
3 years ago
Read 2 more answers
A 79.7 kg base runner begins his slide into second base while moving at a speed of 4.77 m/s. The coefficient of friction between
SashulF [63]

To solve this problem we will apply the concept related to the kinetic energy theorem. Said theorem states that the work done by the net force (sum of all forces) applied to a particle is equal to the change experienced by the kinetic energy of that particle. This is:

\Delta W = \Delta KE

\Delta W = \frac{1}{2} mv^2

Here,

m = mass

v = Velocity

Our values are given as,

m = 79.7kg

v = 4.77m/s

Replacing,

\Delta W = \frac{1}{2} (79.7kg)(4.77m/s)^2

\Delta W = 907J

Therefore the mechanical energy lost due to friction acting on the runner is 907J

6 0
3 years ago
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