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netineya [11]
3 years ago
5

During crystallisation the crystals separate out from the hot ________solution of a substance on cooling

Physics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

The process of separation or deposition of crystals from a hot saturated solution on gentle cooling of the solution is called 'crystallisation'.

Explanation:

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True or false: Everything in the universe works with harmony because of balanced energy
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Explanation:

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3 years ago
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I am drowning in his silence
damaskus [11]

Correct answer choice for question 1 is:


A) Figurative language


Explanation:


Figurative language uses terms of speech to be more powerful, effective, and impactful. Characters of speech such as metaphors, similes, and implications go away the usual meanings of the words to give users new acumens. On the other hand, alliterations, imageries, or echoes are symbolic tools that review the minds of the users. Figurative language can perform in various forms with the use of various literary and eloquent articles.


Correct answer choice for question 2 is :


D) Words that trigger the imagination to remember by appealing to the five senses


Explanation:


Imagery, in a literary text, is an author's use of rich and detailed language to add intensity to their work. It advances to human senses to increase the reader's knowledge of the work. Powerful kinds of comparison join all of the senses. There are seven main kinds of imagery, each resembling a sense, feeling, action, or reaction. Olfactory imagery concerns, scents, or the sense of smell. Gustatory imagery concerns tastes or the sense of taste. Tactile imagery concerns physical forms or the feeling of touch.


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Como anticipan la caída del proyectil, con movimiento parabólico para que el misil no haga daño
Elena L [17]

Answer:

Conociendo la velocidad inicial del proyectil y el angulo de lanzamiento con respecto ala horizontal.

Explanation:

Para poder anticipar la caída del proyectil es importante conocer la velocidad inicial del proyectil y el angulo de disparo del proyectil con respecto a la horizontal.

A continuación se presenta un diagrama o esquema donde se pueden ver estas variables y se explicaran a la brevedad:

Para poder encontrar el rango que es la máxima distancia horizontal recorrida por el proyectil debemos utilizar la siguiente ecuación:

x=(v_{o})_{x} *t\\where:\\(v_{o})_{x} = velocidad inicial  x-component [m/s]\\t= time [s]

Para poder encontrar el tiempo debemos utilizar la siguiente ecuación:

y=(v_{y} )_{o}*t-0.5*g*t^{2}  \\donde:\\(v_{y} )_{o}= velocidad inicial componente y [m/s]\\g = gravity = 9.81 [m/s^2]\\t = time [s]

En la anterior ecuación, igualamos y = 0, ya que cuando el proyectil cae al suelo la distancia vertical es cero. De esta manera podemos encontrar el tiempo t, ya que conocemos la velocidad inicial del proyectil en la componente y.

Seguidamente reemplazamos t en la primera ecuacion y encontramos la distancia x o el rango.

8 0
4 years ago
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