Mirror formula
1/f = (1/p) + (1/q) [ f= focal length , p= object distance , q = image distance ]
as given convex mirror so
distance of object =p= 6cm
focal length = -8cm
to find q=?
1/q =( 1/f) - (1/ p)
1/q = (1/ 8) -(1/6)
1/q =-1/24
q=-24 ( negative sign shows image is virtual and behind the mirror)
That's a 'direct' or 'proportional' variation.
The variables are related by the equation Y = K X .
That constant ratio is the number ' K ' .
The answer is already in the blank for, its was greater
Answer:
115.3 is the direction of the vector. Just learned some physics to get this answer over the past 3 hrs
FOCAL LENGTH = 9.5cm
i° e° d°
30 43 69
40 41 61
45 39 56
50 37 48
65 41 37
plot a graph of d° against i°
from the graph Determine;
(i) the minimum deviation and the corresponding angle of incidence
(ii) the maximum deviation and the corresponding angle of incidence
n=sin(A+D÷2)÷(sinA÷2)
Determine the error in n and explain why it is not advisable to use small values of i° in performing this experiment.
