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Sveta_85 [38]
3 years ago
15

A scientist has decided to develop a new cancer treatment. She has observed how patients react to current treatments, how the tr

eatments function when they encounter cancer cells, and how cancer cells behave in the body. What should she do next?​

Chemistry
2 answers:
sergeinik [125]3 years ago
7 0

Answer:

A) make a plan of what approach she will take to treat cancer

Explanation:

a p e x.

aleksandrvk [35]3 years ago
6 0

Answer:

A) make a plan of what approach she will take to treat cancer

Explanation:

ap3x

You might be interested in
Given 0.02 of KF, how many liters of solution are needed to make a 7.2 solution?
Dmitry_Shevchenko [17]

Answer:

1/360

Explanation:

let x = liters

molarity=moles of solute/liters of solution, 7.2=0.02/x or 7.2=(1/50)(1/x), 7.2(50)=(1/x), 360(x)=1, x=1/360

7 0
3 years ago
What is the [OH-] in a solution with a poh of 3.90
zheka24 [161]

Answer:

7.9433E-3

Explanation:

POH=-log OH

3.90=POH

OH=ANTILOG OF -3.90

=7.9433×10^-3

8 0
3 years ago
Read 2 more answers
The element gallium has an atomic weight of 69.7 and consists of two stable isotopes gallium -69 and gallium -71. The isotope ga
BigorU [14]

Answer:

The answer to your question is Gallium-71 = 70.9202 amu

Explanation:

Gallium atomic weight = 69.7

Gallium-69 = 68.9 amu    abundance = 60.4%

Gallium-71 =     x                abundance = 39.6%  

To solve this problem just write an equation and solve it for the mass of gallium-71.

Equation

Gallium = Gallium-69(abundance) + Gallium-71(abundance)

Substitution

69.7 = (68.9)(0.604) + Gallium-71(0.396)

69.7 = 41.6156 + Gallium-71(0.396)

Gallium-71(0.396) = 69.7 - 41.6156

Gallium-71(0.396) = 28.0844

Gallium-71 = 28.0844/0.396

Gallium-71 = 70.9202 amu

3 0
3 years ago
Which molecule is a substrate dipeptide, water or amino acid?
Leona [35]
Amino acids.
Amino acids group together to form proteins. Enzymes are protein in nature. Thus the substrate is an amino acid.

Hope it helped!
5 0
4 years ago
A chemistry student needs 65.0 mL of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Phy
Anna007 [38]

Answer:

103.3 g

Explanation:

Data Given:

Volume of carbon tetrachloride (v) = 65.0 mL

Density of carbon tetrachloride (d) = 1.59 g/cm³

Solution:

Convert volume of carbon tetrachloride from ml to cm³

1 ml = 1 cm³

so,

65.0 mL = 65.0 cm³

Formula used to calculated mass of carbon tetrachloride should be taken for experiment.

                   d = m/v

Rearrange the above equation:

                   m = d x v . . . . . . .(1)

Put values in equation 1

                   m = 1.59 g/cm³ x 65.0 cm³

                   m = 103.3 g

6 0
3 years ago
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