Answer : The correct expression for equilibrium constant will be:
![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,
The expression of 
will be,
Therefore, the correct expression for equilibrium constant will be,
Answer:
0.0308 mol
Explanation:
In order to convert from grams of any given substance to moles, we need to use its molar mass:
- Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2
- Molar mass of KAI(SO₂)₂ = 194 g/mol
Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:
- 5.98 g ÷ 194 g/mol = 0.0308 mol
The reaction that would take place if hot tungsten was
surrounded by air is that it would react to the oxygen in air to form non
conducting tungsten oxide and burns out instantly.
Answer:
45.4 L
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 27.9 L
V₂ = ?
P₁ = 732 mmHg
P₂ = 385 mmHg
T₁ = 30.1 ºC
T₂ = -13.6 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (30.1 + 273.15) K = 303.25 K
T₂ = (-13.6 + 273.15) K = 259.55 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 45.4 L</u>
