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Naddika [18.5K]
3 years ago
12

Limestone is made of predominantly calcium carbonate. Geologists can test for limestone using hydrochloric acid. The products ar

e calcium chloride, carbon dioxide, and water.
1. Write the balanced equation.

2. How many grams of calcium chloride would be produced from the complete reaction of 35.0g of HCl

3. Determine the limiting reactant, theoretical yield, and percent yield of a reaction in which 5.00 grams of calcium carbonate was reacted with 1.00 grams of hydrochloric acid, and 0.58 grams of carbon dioxide gas was produced?
Chemistry
1 answer:
Blizzard [7]3 years ago
7 0
I'm obsessed with me as much as you
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Water and ammonia molecules are roughly the same size and the same mass but ammonia boils at -28F (-33C) and water boils at 212F
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Answer:

Explanation:

The Ideal Gas Law states that PV=nRT.

Rearrange that into P/n=RT/V.

In this case, the cylinder is rigid so the volume, V, does not change.

Temperature does not change either.

Out of 450 grams of gas, 150 grams leak out. So only 450-150 = 300 grams is left.

n is number of moles which is dependent on mass:

n1/n2 = 450/300 = 3/2

P1/n1 = RT/V = P2/n2

P2 = P1/n1*n2

= 7.2/3*2

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Argon has three naturally occurring isotopes: argon-36, argon-38, and argon-40. Based on argon's reported atomic mass, which iso
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Hydrogen cyanide is used to prepare sodium cyanide, which is used in part to obtain gold from gold-containing rock. If a reac- t
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Answer:

Mass of HCN produced = 6.75 g

Explanation:

Reaction is as follows:

2NH_3+3O_2+2CH_4 \rightarrow 2HCN + 6H_2O

First calculate the no. of moles of each chemical species.

molecular mass of NH_3 is 17 g/mol

No. of mol of NH_3 = 11.5/17 = 0.676 mol

Molecular mass of O_2 = 32 g/mol

No. of  mol of O_2 = 12/32 = 0.375

Molecular mass of CH_4 = 16 g/mol

No. of  mol of CH_4 = 10.5/16 = 0.656 mol

from the balanced chemical reaction, it is clear that 2-moles ammonia reacts with 3 moles oxygen and 2 moles methane to form 2 moles of HCN.

or, 1-mol ammonia reacts with 1.5 mol oxygen and 1 mol methane to form 1 mol of HCN.

Thus, no. of oxygen present is less than required and so it will act as limiting reagent.

From the chemical equation,

3 moles oxygen produces 2 moles HCN

or one mole oxygen produces (2/3) moles HCN

0.375 moles oxygen produces (2/3) × 0.375 HCN = 0.25 moles of HCN  

molar mass of HCN = 27 g/mole

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mass of HCN = 27 × 0.25 = 6.75 g

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Put in order from smallest to largest radii:
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Answer:

1. Ar, Cl, Al, Mg, Na

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