Answer:
NO2(g) + H2O(l) → NO3-(aq) + 2 H+(aq) + 1 e-
Explanation:
Let’s balance the half reaction step by step (in an acidic solution):
• Balance the non-hydrogen and non-oxygen elements first
NO2(g) → NO3-(aq) (N: balanced)
• Balance oxygen by adding H2O to the side that needs oxygen (1 O : 1 H2O)
NO2(g) + H2O(l) → NO3-(aq)
• Balance hydrogen by adding H+ to the side that needs hydrogen (1 H : 1 H+)
NO2(g) + H2O(l) → NO3-(aq) + 2 H+(aq)
• Balance the charges: add electrons to the more positive side (or less negative side)
NO2(g) + H2O(l) → NO3-(aq) + 2 H+(aq)
Reactants Products
0 (-1) + (+1 x 2) = +1
+ 1 e- ____ _______
0
NO2(g) + H2O(l) → NO3-(aq) + 2 H+(aq) + 1 e- → balanced half reaction
The problem mentioned that the half reaction is an oxidation reaction, and the balanced reaction is an oxidation reaction because it lost an electron