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Valentin [98]
3 years ago
7

Say I grab a bunch of aluminum foil (9.5g) and ball it up. Aluminum has a specific heat of .9J/g*C. How much would the aluminum’

s temperature change if I added 67Joules of energy (Q) to it?
Chemistry
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

ΔT = 0.78 °C

Explanation:

Given data:

Mass of Al = 9.5 g

Specific heat capacity of Al = 0.9 J/g.°C

Temperature change = ?

Heat added = 67 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

67 J = 9.5 g × 0.9 j/g.°C × ΔT

67 J = 85.5 j/°C × ΔT

ΔT = 67 J  /  85.5 j/°C

ΔT = 0.78 °C

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Calculate the percent dissociation of trimethylacetic acid(C6H5CO2H) in a aqueous solution of the stuff.
Sophie [7]

Answer:

1.112%.

Explanation:

Step one : write out the correct acid dissociation reaction. This is done below:

C6H5CO2H <=====> C6H5CO2^- + H^+.

At equilibrium, the concentration of C6H5CO2H = 0.5 M - x and the concentration of C6H5CO2^- = x and the concentration of H^+ = x.

The ka for C6H5CO2H = 6.3 × 10^-5.

Step two: find the value for the concentration of C6H5CO2^- and H^+. This can be done by using the equilibrium dissociation Constant formula below;

Ka = [C6H5CO2^- ] [H^+] / C6H5CO2H.

ka = [x] [x] / [0.5 - x].

6.3 × 10^-5 = (x)^2 / [0.5 - x].

x^2 = 3.15 ×10^-5 - 6.3 × 10^-5 x.

x^-2 + 6.3 × 10^-5 x - 3.15 × 10^-5.

Solving for x we have x= 0.0055632289702004 = 0.00556.

Therefore, at equilibrium the concentration of H^+ = 0.00556 M and the concentration of C6H5CO2H= O.5 - 0.00556 = 0.494 M.

Step three: Calculate the equilibrium pH. This stage can be ignored for this question since we are not asked to calculate for the pH.

The formular for pH = - log [H^+].

pH= - log [0.00556].

pH= 2.255.

Step four: find the percentage dissociation.

Percentage dissociation = ( [H^+] at equilibrium/ [ C6H5CO2H] at Initial concentration ) × 100%.

Percentage dissociation=( 0.00556/ 0.5 ) × 100.

=Percentage dissociation= 1.112%.

3 0
4 years ago
Which of the following statements is NOT true?
maria [59]

Answer : The incorrect statements are:

(A) When two nonmetals react, the compound formed is ionic.

(B) Two nonmetals can undergo an oxidation-reduction reaction.

Explanation :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

The two nonmetals can not undergo an oxidation-reduction reaction.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The metal-nonmetal reaction can always be assumed to be an oxidation-reduction reaction.

For example : 2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

In this reaction, sodium shows oxidation because the oxidation state changes from (0) to (+1) and and chlorine shows reduction because the oxidation state changes from (0) to (-1).

Hence, the incorrect statements are, (A) and (B)

8 0
4 years ago
Which compound is an isomer of CH3CH2OH?
Aleksandr-060686 [28]
A)CH3OCH3 is the isomer of CH3CH2OH
8 0
3 years ago
This one is more like history then chem
alekssr [168]

Hello !!

I think the answer will be is :

<h2>B. Elements are different kinds of atoms.</h2><h2></h2>

Because when the atom changed it's means it's different types of the atom.

Hope It Helped!

<u>And Tell me if The answer is wrong. . .</u>

<u />

<u>Good Luck With Your Assignment!</u>

<u></u>

#LearnWiithBrainly

\frac{A~n~s~w~e~r~:}{}

Jace ^-^

8 0
3 years ago
Which has a higher melting point, NaBr or KBr
Blababa [14]
NaBr melting point : 1,377°F (774C)
KBr: 1,353°F (734C)
7 0
4 years ago
Read 2 more answers
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