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Valentin [98]
3 years ago
7

Say I grab a bunch of aluminum foil (9.5g) and ball it up. Aluminum has a specific heat of .9J/g*C. How much would the aluminum’

s temperature change if I added 67Joules of energy (Q) to it?
Chemistry
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

ΔT = 0.78 °C

Explanation:

Given data:

Mass of Al = 9.5 g

Specific heat capacity of Al = 0.9 J/g.°C

Temperature change = ?

Heat added = 67 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

67 J = 9.5 g × 0.9 j/g.°C × ΔT

67 J = 85.5 j/°C × ΔT

ΔT = 67 J  /  85.5 j/°C

ΔT = 0.78 °C

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6 0
3 years ago
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7 0
3 years ago
Which of these types of changes is a physical change?
Cloud [144]

Answer:

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6 0
2 years ago
Calculate the amount of solute needed for 1000 ml of 15% sodium thiosulfate
maksim [4K]
15% =  15 grams of solute in 100 mL solution

15 g --------------- 100 mL
?? ------------------ 1000 mL

1000 x 15 / 100 = 

15000 / 100 => 150 g of solute

hope this helps!
7 0
3 years ago
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