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MArishka [77]
3 years ago
11

The products of the reaction CaF2 + Br2 → CaBr2 + F2 are formed by reacting calcium fluoride with bromine. If equal moles of eac

h reactant were present, what would be the limiting reactant?
Chemistry
1 answer:
yuradex [85]3 years ago
8 0

Answer:

there is no limiting reactant.

Explanation:

Given that:

CaF₂  +  Br₂  ----->     CaBr₂  + F₂

From the above equation;

We can see that there is an equal number of moles in the reactant side of the equation.

i.e.

one mole of CaF₂  reacts with one mole of Br₂.

Thus, there is no limiting reactant.

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Gallium oxide, Ga.Oy, forms when gallium is combined with oxygen. A 1.25 g of Ga is allowed to react with excess oxygen and 1.68
mrs_skeptik [129]

Answer : The chemical formula of a compound is, Ga_2O_3

Solution :  Given,

Mass of gallium = 1.25 g

Mass of gallium oxide = 1.68 g

Mass of oxygen = Mass of gallium oxide - Mass of gallium

Mass of oxygen = 1.68 - 1.25 = 0.43 g

Molar mass of Ga = 69.72 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of Ga = \frac{\text{ given mass of Ga}}{\text{ molar mass of Ga}}= \frac{1.25g}{69.72g/mole}=0.0179moles

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.43g}{16g/mole}=0.027moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ga = \frac{0.0179}{0.0179}=1

For O = \frac{0.027}{0.0179}=1.5

The ratio of Ga : O = 1 : 1.5

To make in whole number we multiple ratio by 2, we get:

The ratio of Ga : O = 2 : 3

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = Ga_2O_3

The empirical formula weight = 2(69.72) + 3(16) = 187.44 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{187.44}{187.44}=1

Molecular formula = (Ga_2O_3)_n=(Ga_2O_3)_1=Ga_2O_3

Therefore, the chemical of the compound is, Ga_2O_3

5 0
3 years ago
if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be adde
polet [3.4K]

Answer:

14.91 mL

Explanation:

<em>Assuming the weak acid is monoprotic</em>, we can solve this problem using the equation:

  • C₁V₁=C₂V₂

Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.

We <u>input the data</u>:

  • 25.00 mL * 0.1084 M = 0.1817 M * V₂

And solve for V₂:

  • V₂ = 14.91 mL
6 0
3 years ago
An unknown liquid has a mass of 4.25 × 108 mg and a volume of 0.250 m3. what is the density of the liquid in units of g/ml?
mrs_skeptik [129]
Density= mass/volume
             step  one :
  convert  m3  to  ml
1m^3  =1000000ml
0.250m^3 x1000000=250000ml
         
           step  two:  convert  mg   to  g
 1mg=0.001g,  therefore 4.25 x108mg=0.459g
density  is  therefore= 0.459g/250000=1.836 x10^-6g/ml
8 0
4 years ago
Read 2 more answers
A patient in need of treatment for the correction of a malocclusion would visit a/an
wariber [46]
A malocclusion is the t<span>he unusual alignment of the upper and lower teeth. The patient should visit an ORTHODONTIST to get his teeth corrected.</span>
4 0
3 years ago
This is due in five mintues please help
Fittoniya [83]

Answer:

5

Explanation:

Na, N, O, O, O

5 0
3 years ago
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