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andrew-mc [135]
3 years ago
14

Angela was instructed on a test to make an analogy, or comparison, for polymers. She writes four examples of how polymers are li

ke pearl necklaces. She has many parts to this analogy that make sense, but one part of her analogy does not fit.
Which is the most likely error in her analogy?
Chemistry
2 answers:
erica [24]3 years ago
8 0

Answer:

B

Explanation:

I took the test

inessss [21]3 years ago
6 0
The correct option is this: THE THREAD THAT CONNECTS THE PEARLS IS LIKE AN IONIC BOND.
The type of bond that connect polymers is not ionic bond. Polymers are made up of non metals and carbon is the most common element in polymers. Molecules in polymers are usually connected together by covalent bonds.
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Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO
Irina-Kira [14]

Answer : The enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of H_2SO_4 will be,

S+H_2+2O_2\rightarrow H_2SO_4    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) S+O_2\rightarrow SO_2     \Delta H_1=-298.2

(2) SO_2+\frac{1}{2}O_2\rightarrow SO_3    \Delta H_2=-98.2

(3) SO_3+H_2O\rightarrow H_2SO_4    \Delta H_3=-130.2

(4) H_2+\frac{1}{2}O_2\rightarrow H_2O    \Delta H_4=-285.8

Now adding all the equations, we get the expression for enthalpy of formation of H_2SO_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4

\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)

\Delta H=-812.4kJ/mol

Therefore, the enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

3 0
3 years ago
Reactivity occurs when a substance reacts with another substance, changing it into a ____?
MakcuM [25]

Answer:b

Explanation:

6 0
2 years ago
What would the formula of gallium<br> bromide be?
Free_Kalibri [48]
GaBr3

Gallium=Ga
Bromine= Br
Bromide=Br3
5 0
3 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?
Inessa [10]

A sample of a compound contains 60.0 g C and 5.05 g H.

divide by molar mass of C(12) and H(1) to get molar ratio

C: 60/12=5 and H: 5/1=5

so C:H=5:5=1:1

total molar mass=78

divide by 1C+1H to find the formula: 78/(12+1)=78/13=6

compound is C6H6


5 0
3 years ago
Read 2 more answers
What is the molarity if I take 10mL of 20 volumes Hydrogen Peroxide?
Kryger [21]

Answer:

1.635 M

Explanation:

Given:

10 mL of 20 volumes Hydrogen Peroxide

Here,

20 volumes of Hydrogen Peroxide means that on decomposition of 1 mL of H₂O₂ 20 mL of O₂ is obtained

also,

means 1 dm³ of H₂O₂ solution produces 20 dm³ oxygen

Now,

at 298K and 1 atm

20 dm³ oxygen = \frac{\textup{20}}{\textup{24.47}}  moles

or

= 0.817 moles

also,

2H₂O₂ → 2H₂O + O₂

thus,

1 dm³ of solution must contain 2 × moles of O₂ as moles of H₂O₂

thus,

Number of moles of H₂O₂ = 2 × 0.817

or

Number of moles of H₂O₂  = 1.635 moles

Hence,

For 20 volume hydrogen peroxide is 1.635 M

3 0
3 years ago
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