All categories

3 years ago

How do you make these equations balanced?

Chemistry

1 answer:

Sedaia [141]3 years ago

3 0

Explanation:

both iron and sulphur in FeS2 undergo a change in oxidation state.

O2° -->2O degree2- Total decrease = 2×2=4

So, 4FeS2+11O2 --> 2Fe2O3+8 SO2

Hence, balanced

You might be interested in

Plz help with this........

Elodia [21]

<h2>GREETINGS!</h2><h2>_____________________________________</h2><h3>Answer:</h3>

ITS $C_{4}H_{10}$ AND $C_{5}H_{12}$

<h2>_____________________________________</h2><h3><u>GENERAL FORMULA OF ALKANE</u></h3><h3> $C_{n}H_{2n+2}$ </h3>

Where n is the number of CARBONS

By using the General Formula of Alkanes having 4 carbon atoms is

$C_{4}H_{2x4+2}$

$C_{4}H_{10}$

By using the General Formula of Alkanes having 5 carbon atoms is

$C_{5}H_{2x5+2}$

$C_{5}H_{12}$

IF YOU USE THE SAME FORMULA FOR THE OTHER TWO OPTIONS THE OUTCOME WILL NOT BE AS SAME AS GIVEN IN THE QUESTION SO THOSE TWO ARE CAN NOT BE OUR ANSWER

<h2>_____________________________________</h2><h2>HOPE THIS HELPS!</h2>

3 0

3 years ago

How can a change to another population could affect births and deaths in the parrot population.

forsale [732]

Answer:

read it first

Explanation:

Population change is governed by the balance between birth rates and death rates. If the birth rate stays the same and the death rate decreases, then population numbers will grow. If the birth rate increases and the death rate stays the same, then population will also grow.

hope it helps

6 0

2 years ago

Complete and balance the reaction in acidic solution. equation: ZnS + NO_{3}^{-} -> Zn^{2+} + S + NO ZnS+NO−3⟶Zn2++S+NO Which

kotykmax [81]

Answer:

Balanced reaction: $3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

S is oxidized and N is reduced.

$NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: $ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO$

$\Rightarrow$ Oxidation: $ZnS\rightarrow Zn^{2+}+S$

Balance charge: $ZnS-2e^{-}\rightarrow Zn^{2+}+S$ ...............(1)

$\Rightarrow$ Reduction: $NO_{3}^{-}\rightarrow NO$

Balance H and O in acidic medium : $NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O$

Balance charge: $NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O$ ...............(2)

[ $3\times$ Equation-(1)] + [ $2\times$ Equation-(2)]:

$3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of $NO_{3}^{-}$ to NO. Therefore N is reduced.

$NO_{3}^{-}$ consumes electron from ZnS. Therefore $NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

7 0

4 years ago

Sio2(s)+3c(s)→sic(s)+2co(g)

bonufazy [111]

Please explain in more detail

7 0

3 years ago

I need help FAST ASAP

kiruha [24]

In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.

1. Na⁺ , Cl⁻ , NaCl ---> sodium chloride (this is most commonly known as table salt)

2. C⁴⁺ , O²⁻ , CO₂ ---> carbon dioxide

3. Al³+ , Cl⁻ , AlCl₃ ----> aluminum chloride

4. Ca²⁺ , Cl⁻ , CaCl₂ ---> calcium chloride

5. Li⁺ , Br⁻ , LiBr ---> lithium bromide

6. Mg³⁺ , O²⁻ , Mg₂O₃ ----> magnesium oxide

7. K⁺ , I⁻ , KI ---> potassium iodide

8. H⁺ , Cl⁻ , HCl --> hydrogen chloride

9. H⁺ , Br⁻ , HBr ----> hydrogen bromide

10. Na⁺ , Br⁻ , NaBr ---> sodium bromide

6 0

4 years ago