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NeX [460]
3 years ago
11

Can you draw the peptide structure at pH 7.0 (including peptide bonds)

Chemistry
1 answer:
ELEN [110]3 years ago
7 0

Answer:

See image below

Explanation:

The image is labeled according to the sequence N'-Trp-Ser-Asg-Gly-Cys-His-COOH' which means that in the main chain of the peptide, the amino group of the Tryptophan and the carboxylic group of the Histidine are free and thus its charge depends on the pH; other groups that rely on the pH are the side groups of the Cysteine and the Histidine.

Overall, ionizable groups in this peptide are:

  • Amino Group of the Tryptophan (pKa = 9.39)
  • SH group of the Cysteine (pKa = 8.18)
  • Secondary amine of the Histidine (pKa = 6.00)
  • Carboxylic Group of the Histidine (pKa = 1.82)

Then, the amino group of Trp and SH group of Cys are protonated since the peptide is at a pH below the pKa. The secondary amine of the Histidine is deprotonated because the pH is greater than the pKa, as well with its carboxylic acid group.

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Greenhouse gases act to __________ temperatures by __________ thermal infrared radiation. Group of answer choices increase; refl
Harlamova29_29 [7]

Greenhouse gases act to <u>increase</u> temperatures by <u>absorbing</u> thermal infrared radiation.

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The multiplied quantities of greenhouse gases human sports are adding to the environment have dissatisfied the balance that has been in location for the reason that ceases of the closing ice age, including greater greenhouse gases decreases the amount of infrared radiation energy leaving the atmosphere.

Greenhouse gases inside the ecosystem time and again absorb and re-radiate infrared radiation (warmth). strength radiated from Earth's surface as warmth, or infrared radiation is absorbed and re-radiated by using greenhouse gases, impeding the loss of warmth from our surroundings to area.

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4 0
1 year ago
One of the compounds used to increase the octane rating of gasoline is toluene (pictured). Suppose 43.3 mL of toluene (d = 0.867
Thepotemich [5.8K]

<u>Answer:</u>

(A)

Density = Mass / Volume

So  

Mass = Density × Volume

= 0.867 g/mL \times 43.3mL = 37.5411 g Toluene

1C_6 H_5 CH_3  + 9 O_2  > 7 CO_2  + 4 H_2 O

Mole ratio of toluene : Oxygen is 1 : 9

$37.5411 g \text { Toluene } \times \frac{1 \text {mol} \text {toluene}}{92 g \text { toluene}} \times \frac{9 {mol} O_{2}}{1 \text {mol} \text { toluene }} \times \frac{32 g O_{2}}{1 {mol} O_{2}}=117 g O_{2}(\text {Answer})$

(B)

1 mole of Toluene produces 7 moles of CO_2 gas and 4 moles of H_2 O Vapour

So the mole ratio is 1 : 11

37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene }} \times \frac{11 \mathrm{mol} \text { gas }}{1 \text { mol toluene }} $$\\\\=4.49 \text { mol gaseous products (Answer) } $

(C)

1mole contains 6.022\times10^{23} molecules

37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene}} \times \frac{4 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \text { toluene }} \times \frac{6.022 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}} $\\\\$=9.82 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O} \text { (Answer) } $

6 0
3 years ago
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Crazy boy [7]

Answer:

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Explanation:

8 0
3 years ago
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SSSSS [86.1K]

Answer:

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Explanation:

please mark brianliest :)

4 0
3 years ago
Ignore this!<br><br>i got the answer already haha
marta [7]

Answer:

okay lol, ima use this for points if okay

Explanation:

5 0
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