Can you draw the peptide structure at pH 7.0 (including peptide bonds)
1 answer:
Answer:
See image below
Explanation:
The image is labeled according to the sequence N'-Trp-Ser-Asg-Gly-Cys-His-COOH' which means that in the main chain of the peptide, the amino group of the Tryptophan and the carboxylic group of the Histidine are free and thus its charge depends on the pH; other groups that rely on the pH are the side groups of the Cysteine and the Histidine.
Overall, ionizable groups in this peptide are:
- Amino Group of the Tryptophan (pKa = 9.39)
- SH group of the Cysteine (pKa = 8.18)
- Secondary amine of the Histidine (pKa = 6.00)
- Carboxylic Group of the Histidine (pKa = 1.82)
Then, the amino group of Trp and SH group of Cys are protonated since the peptide is at a pH below the pKa. The secondary amine of the Histidine is deprotonated because the pH is greater than the pKa, as well with its carboxylic acid group.
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Answer:
Five peaks
Explanation:
GaAs would show two peaks:
Ga-69 + As-75 = 144
Ga-71 + As-75 = 146
Their intensities are in the ratio 60 : 40 = 100:67.
Ga₂S₂ would show three peaks:
Ga-69 + Ga-69 + 2As-75 = (Ga-69)₂(As-75)₂ = 288
Ga-69 + Ga-71 + 2As-75 = (Ga-69)(Ga-71(As-75)₂ = 290
Ga-71 + Ga-71 + 2As-75 = (Ga-71)₂(As-75)₂ = 292
Their relative intensities are in the ratio
(60 + 40)² = 60² : 2×60×40 : 40² = 3600 : 4800 : 1600 = 75 : 100 : 33
A spectrum of a mixture of GaAs and Ga₂As₂ would show five peaks:
Two at m/e 144 and 146 with intensity ratios 100: 67 and
Three at m/e 288, 290, and 292 with intensity ratios 75:100 :33.
We cannot predict the absolute sizes of the peaks because we do not know the relative amounts of GaAs and GaAs₂.
Answer:
1s2: correct.
6s3: incorrect because the subshell s can hold up to 2 electrons.
5f10: correct.
4d3: correct.
2d4: incorrect because the second energy level just has the s and p subshells.
3p10: incorrect because the p subshell can hold up to 6 electrons.
Explanation:
Hello there!
In this case, according to the attached file, which shows the correct orbitals and electrons, we can proceed as follows:
1s2: correct.
6s3: incorrect because the subshell s can hold up to 2 electrons.
5f10: correct.
4d3: correct.
2d4: incorrect because the second energy level just has the s and p subshells.
3p10: incorrect because the p subshell can hold up to 6 electrons.
Best regards!
It equals 0.005 but plz mark this as the brainliest question plz
