Answer:
See explaination
Explanation:
for a reverse carnot cycle T-S diagram is a rectangle which i have shown
net work for a complete cycle must be equal to net heat interaction.
Kindly check attachment for the step by step solution of the given problem.
Answer:
AC: at D , M_max = 12.25 lb-ft
BC: at E , M_max = 8.75 lb-ft
Explanation:
Given:
- The diameter of the pipe d = 5-in
- The pipe is supported every L = 9 ft of pipe in length
- The weight if the pipe + contents W = 10 lb/ft
Find:
determine the magnitude and location of the maximum bending moment in members AC and BC.
Solution:
- The figure (missing) is given in the attachment.
- We will first determine the external forces acting on each member:
Section: 9-ft section of pipe.
Sum of forces perpendicular to member AC = 0
F_d - 0.8*W*L = 0
F_d = 0.8*10*9 = 72 lb
Sum of forces perpendicular to member BC = 0
F_e - 0.6*W*L = 0
F_e = 0.6*10*9 = 54 lb
F_d = 72 lb , F_e = 54 lb
- Then we will determine the support reactions for each member AC point A and BC point B.
Section: Entire Frame.
Sum of moments about point B = 0
-A_y*(18.75/12) + F_d*(d /2*12) + F_e*((11.25-2.5)/12) = 0
-A_y*(1.5625) + 15 + 39.375 = 0
A_y = 34.8 lb
Sum of forces in vertical direction = 0
A_y + B_y - 0.8*F_d - 0.6*F_e = 0
B_y = 0.8*(72) + 0.6*(54) - 34.8
B_y = 55.2 lb
Sum of forces in horizontal direction = 0
A_x + B_x - 0.6*F_d + 0.8*F_e = 0
A_x + B_x = 0
Section: Member AC
Sum of moments about point C = 0
F_d*(2.5/12) - A_y*(12/12) - A_x*(9/12) = 0
72*2.5 - 34.8*12 - 9*A_x = 0
A_x = -237.6 / 9 = - 26.4 lb
B_x = - A_x = 26.4 lb
A_x = -26.4 lb , B_x = 26.4 lb
- Now we will calculate bending moment for each member at different sections.
Member AC:
From point A till just before point D
-0.6*A_x*x - A_y*0.8*x + M = 0
15.84*x - 27.84*x + M = 0
M = 12*x ..... max value at D, x = 12.25 in
M_max = 12*12.25/12 = 12.25 lb-ft
Member BC:
From point B till just before point E
-0.8*B_x*x + B_y*0.6*x + M = 0
-21.12*x + 33.12*x + M = 0
M = -12*x ..... max value at E, x = 11.25 - 2.5 = 8.75 in
M_max = -12*8.75/12 = -8.75 lb-ft
- The maximum bending moments and their locations are:
AC: at D , M_max = 12.25 lb-ft
BC: at E , M_max = 8.75 lb-ft
Answer:
The question is explained in detailed way in explanation section and in attached files.
Explanation:
The HIPAA Security Rule is designed to be flexible and appropriate for our organization’s particular size, structure, and inherent risks to business and personal information. Risk analysis is meant to be an ongoing process, during which we regularly review our records to track access to business and personal systems and data. With this in mind, I recommend that we expand our information security strategy to include more than just what is required in HIPAA. Just as a reminder below is the HIPAA ecompliance and implementation strategy that we came up with last week as given in attached file 1.
There are several areas in IT security that the above is incomplete or insufficient in. We recommend implementing several more complete or alternative controls in order to protect our systems, patients, employees, contractors, vendors, and assets beyond the HIPAA minimum requirements. The below section describes what the Centers for Medicare and Medicaid Services (CMS) recommend as additional areas to focus on in the effort to increase an organization's security. (See the attached file # example of some of the areas that we should monitor beyond what HIPAA requires are given in attached file # 03.
Answer:
Explanation:
From the question we are told that:
Zener diode Voltage
Zener diode Current
Note
Supply Voltage
Reduction Percentage
Generally the equation for Kirchhoff's Voltage Law is mathematically given by
Therefore
Generally the equation for Kirchhoff's Current Law is mathematically given by
Therefore