Answer:
Time taken = 136.32 minutes
Explanation:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
The watts that are consumed is 80 watts.
<h3>What power factor?</h3>
The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.
Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have; V × I × PF = 100V × 4A × 0.2 = 80 watts.
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Answer:
Hello your question has some missing information below are the missing information
The refrigerant enters the compressor as saturated vapor at 140kPa Determine The coefficient of performance of this heat pump
answer : 2.49
Explanation:
For vapor-compression refrigeration cycle
P1 = P4 ; P1 = 140 kPa
P2( pressure at inlet ) = P3 ( pressure at outlet ) ; P2 = 800 kPa
<u>From pressure table of R 134a refrigerant</u>
h1 ( enthalpy of saturated vapor at 140kPa ) = 239.16 kJ/kg
h2 ( enthalpy of saturated liquid at P2 = 800 kPa and t = 60°C )
= 296.8kJ/kg
h3 ( enthalpy of saturated liquid at P3 = 800 kPa ) = 95.47 kJ/kg
also h4 = 95.47 kJ/kg
To determine the coefficient of performance
Cop = ( h1 - h4 ) / ( h2 - h1 )
∴ Cop = 2.49