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3 years ago

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A 5-in.-diameter pipe is supported every 9 ft by a small frame consisting of two members asshown. Knowing that the combined weig

ht of the pipe and its contents is 10 lb/ft and neglectingthe effect of friction, determine the magnitude and location of the maximum bending moment inmembersACandBC.

1 answer:

jarptica [38.1K]3 years ago

5 0

Answer:

AC: at D , M_max = 12.25 lb-ft

BC: at E , M_max = 8.75 lb-ft

Explanation:

Given:

- The diameter of the pipe d = 5-in

- The pipe is supported every L = 9 ft of pipe in length

- The weight if the pipe + contents W = 10 lb/ft

Find:

determine the magnitude and location of the maximum bending moment in members AC and BC.

Solution:

- The figure (missing) is given in the attachment.

- We will first determine the external forces acting on each member:

Section: 9-ft section of pipe.

Sum of forces perpendicular to member AC = 0

F_d - 0.8*W*L = 0

F_d = 0.8*10*9 = 72 lb

Sum of forces perpendicular to member BC = 0

F_e - 0.6*W*L = 0

F_e = 0.6*10*9 = 54 lb

F_d = 72 lb , F_e = 54 lb

- Then we will determine the support reactions for each member AC point A and BC point B.

Section: Entire Frame.

Sum of moments about point B = 0

-A_y*(18.75/12) + F_d*(d /2*12) + F_e*((11.25-2.5)/12) = 0

-A_y*(1.5625) + 15 + 39.375 = 0

A_y = 34.8 lb

Sum of forces in vertical direction = 0

A_y + B_y - 0.8*F_d - 0.6*F_e = 0

B_y = 0.8*(72) + 0.6*(54) - 34.8

B_y = 55.2 lb

Sum of forces in horizontal direction = 0

A_x + B_x - 0.6*F_d + 0.8*F_e = 0

A_x + B_x = 0

Section: Member AC

Sum of moments about point C = 0

F_d*(2.5/12) - A_y*(12/12) - A_x*(9/12) = 0

72*2.5 - 34.8*12 - 9*A_x = 0

A_x = -237.6 / 9 = - 26.4 lb

B_x = - A_x = 26.4 lb

A_x = -26.4 lb , B_x = 26.4 lb

- Now we will calculate bending moment for each member at different sections.

Member AC:

From point A till just before point D

-0.6*A_x*x - A_y*0.8*x + M = 0

15.84*x - 27.84*x + M = 0

M = 12*x ..... max value at D, x = 12.25 in

M_max = 12*12.25/12 = 12.25 lb-ft

Member BC:

From point B till just before point E

-0.8*B_x*x + B_y*0.6*x + M = 0

-21.12*x + 33.12*x + M = 0

M = -12*x ..... max value at E, x = 11.25 - 2.5 = 8.75 in

M_max = -12*8.75/12 = -8.75 lb-ft

- The maximum bending moments and their locations are:

AC: at D , M_max = 12.25 lb-ft

BC: at E , M_max = 8.75 lb-ft

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